[英]Perplexing Output of C language program using Turbo C++ 3.0 compiler
Concerning my determination for output.It's 1 40 1 While using C it displays output as 0 41 1 How's that possible?What wrong step I'm going into? 关于我对输出的确定。它是1 40 1在使用C时,它将输出显示为0 41 1这怎么可能?我要走什么错误的步骤?
#include<stdio.h>
#include<conio.h>
void main(void)
{
clrscr();
int n,a,b;
n = 400;
a = n % 100; //remainder operation
b = n / 10; //division operation
n = n % 10; //remainder operation
printf("%d %d %d",n++,++b,++a); //post-,pre-,pre- increment used
getch();
}
What your compiler prints is correct. 您的编译器打印的内容正确。 Here is the program flow:
这是程序流程:
#include<stdio.h>
#include<conio.h>
void main(void)
{
clrscr();
int n,a,b;
n = 400; // n has value 400
a = n % 100; // a has value 0
b = n / 10; // b has value 40
n = n % 10; // n has value 0
// n++ evaluates to 0, afterwards n has the value 1
// ++b evaluates to 41, afterwards b has the value 41
// ++a evaluates to 1, afterwards a has the value 1
printf("%d %d %d",n++,++b,++a);
// Thus, 0 41 1 is printed.
getch();
}
Notice especially that the postfix-incrememnt operator n++
returns the value of n
unchanged and then changes n
. 通知特别是后缀-incrememnt操作者
n++
返回的值n
不变,然后改变n
。 That's why 0
is printed in the first column. 这就是为什么在第一列中打印
0
的原因。
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