C++按升序排序数组打印

Question

Im trying to sort an array in ascending order and print it out and Im having trouble of where to put my cout in my code.

for (int k=0; k<ARRAY_SIZE; k++) {
    for (int l=1; l<ARRAY_SIZE-1; l++) {
        if(numbers[l] > numbers[k]) {
            temp = numbers[k];
            numbers[k] = numbers[l];
            numbers[l] = temp;
        }
        cout<<numbers[k];
    }    
}

Answer 1

Remove the actual cout and put it after the sorting loop, in a new loop

for(int k = 0 ; k < ARRAY_SIZE; ++k)
    cout << numbers[k] << " ";

Answer 2

如果要查看排序结果，则必须在新的 for 循环中打印数组

Answer 3

This is a program that finds the length of a number n and converts it to an array arr and sorts that array in ascending order. (possible aptitude question)

#include <iostream>
using namespace std;
int main()
{
    int n,i=0,j,num,temp,len=0,arr[10]={0};
    cin>>n;
    num=n;
while(n!=0)
    {
        len++;
        n/=10;
    }
    cout<<len<<endl;
    for ( i = len; i >= 0; i--)
        {
            arr[i] = num%10;
            num/=10;
    }
for(i=1;i<=len;i++)
    for(j=0;j<=len-i;j++)
{
    if(arr[j]>arr[j+1])
    {
        temp=arr[j];
        arr[j]=arr[j+1];
        arr[j+1]=temp;
    }
}
for(i=1;i<=len;i++)
{
    cout<<arr[i]<<endl;
}
return 0;
}