C++ sorting an array in ascending order Printing

Question

Im trying to sort an array in ascending order and print it out and Im having trouble of where to put my cout in my code.

for (int k=0; k<ARRAY_SIZE; k++) {
    for (int l=1; l<ARRAY_SIZE-1; l++) {
        if(numbers[l] > numbers[k]) {
            temp = numbers[k];
            numbers[k] = numbers[l];
            numbers[l] = temp;
        }
        cout<<numbers[k];
    }    
}

Answer 1

Remove the actual cout and put it after the sorting loop, in a new loop

for(int k = 0 ; k < ARRAY_SIZE; ++k)
    cout << numbers[k] << " ";

Answer 2

如果要查看排序结果，则必须在新的 for 循环中打印数组

Answer 3

This is a program that finds the length of a number n and converts it to an array arr and sorts that array in ascending order. (possible aptitude question)

#include <iostream>
using namespace std;
int main()
{
    int n,i=0,j,num,temp,len=0,arr[10]={0};
    cin>>n;
    num=n;
while(n!=0)
    {
        len++;
        n/=10;
    }
    cout<<len<<endl;
    for ( i = len; i >= 0; i--)
        {
            arr[i] = num%10;
            num/=10;
    }
for(i=1;i<=len;i++)
    for(j=0;j<=len-i;j++)
{
    if(arr[j]>arr[j+1])
    {
        temp=arr[j];
        arr[j]=arr[j+1];
        arr[j+1]=temp;
    }
}
for(i=1;i<=len;i++)
{
    cout<<arr[i]<<endl;
}
return 0;
}