[英]R empty string replacement
I should convert 'N/A' and 'not known' to a blank string “”我应该将 'N/A' 和 'not known' 转换为空白字符串“”
Var1 Freq
1 N/A 650
2 NONE 264
3 NOT KNOWN 58
to be like this像这样
Var1 Freq
1 650
2 264
3 58
and和
"" <- new_building[grepl("N/A|NOT|KNOWN", new_building$Var1),]
I used this but this is not working我用过这个,但这不起作用
> string<-'asdaN/A'
> string2<-gsub(string,pattern='N/A',replacement='')
> string2
[1] "asda"
do you mean this?你是这个意思吗?
Edit: following updated q:编辑:以下更新q:
string<-c('Var1','Freq', '1','N/A','650','2', 'NONE','264', '3', 'NOT KNOWN', '58')
string[!string%in%'N/A']
how about this:这个怎么样:
df_ <- data.frame(Var1 = c('N/A', 'NONE', 'NOT KNOWN'), Freq = c(650, 264, 58))
df_$Var1 <- gsub("N/A|NONE|NOT KNOWN", "", df_$Var1)
df_
# Var1 Freq
#1 650
#2 264
#3 58
your assignment to ""
( "" <- ...
) is very wrong;你对
""
( "" <- ...
) 的分配是非常错误的; i am not sure what your logic is here.我不确定你的逻辑是什么。 the correct approach is to substitute strings satisfying your criteria with empty strings
""
using gsub
.正确的方法是使用
gsub
用空字符串""
替换满足您条件的字符串。
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