AngularJS querySelector通过ID返回未定义

Question

Here is what my index.html looks like:

And this is the Javascript code (angular):

var controllerElement = document.querySelector('[id="tile3"]');
console.log(controllerElement.getAttribute('class'));
var controllerScope = angular.element(controllerElement).scope();

As you can see, I'm trying to find the controllerElement by searching for an id equal to tile3 . However, whenever I get to the next line the program crashes with this error:

Uncaught TypeError: Cannot read property 'getAttribute' of null

Is there something obvious I'm missing?

EDIT

Here is the full code, now the controllerScope var is being undefined for some reason...

var update = function(id, channel){
    var controllerElement = document.querySelector('#tile3');
    console.log(controllerElement.getAttribute('ng-controller'));
    var controllerScope = angular.element(controllerElement).scope();
    console.log(controllerScope);
    controllerScope.$apply(function () {
        controllerScope[id].username = channel.username;
        controllerScope[id].keyword = channel.keyword;
        controllerScope[id].percent = channel.percent;
        controllerScope[id].views = channel.views;
        controllerScope[id].link = channel.link;
    });
};

(function(){
    var app = angular.module("testApp", []);

    var TileController = function($scope){
        $scope.channels = [];
        for(i = 0; i < 25; i++){
            var channel = {
                username:"John",
                keyword:"Doe",
                percent:"50%",
                views:5000,
                link:"http://www.twitch.tv/lolyou"
            };
            $scope.channels.push(channel);
        }

    };

    app.controller("TileController", ["$scope", TileController]);

    update(3, {username:"Yo",
                keyword:"Bro",
                percent:"40%",
                views:35,
                link:"http://www.twitch.tv/nickbunyun"});
})();

The line where it says console.log(controllerScope); is just printing "undefined".

Answer 1

如果使用querySelector，则可以/应该将＃tile3用作传递给函数的值，因此：

var tile3 = document.querySelector('#tile3')