[英]Char variable behavior in C program
I wrote a sudoku solver program with function which checks if it is leagal to set a value in a specific location: 我编写了一个带有功能的数独解算器程序,该程序检查是否可以在特定位置设置值:
typedef int cell;
typedef char value;
typedef value sudokuGrid[GRID_SIZE]; // GRID_SIZE is 81
int isLegal (sudokuGrid game, cell location,value candidateDigit);
I also wrote a function to test isLegal function giving it a sudoku puzzle and once the solution is calculated checking if all set values are correct: 我还写了一个函数来测试isLegal函数,给它一个数独难题,一旦计算出解决方案,就检查所有设置值是否正确:
static void testIsLegal(){
int i, solution;
int mid_result, result;
sudokuGrid testGrid = {
'6','4','.','.','.','.','8','1','7',
'1','7','.','8','6','.','2','.','4',
'.','.','.','.','.','.','.','9','6',
'.','8','.','.','9','6','.','.','.',
'.','6','.','3','.','1','.','2','.',
'.','.','.','2','5','.','.','6','.',
'8','2','.','.','.','.','.','.','.',
'3','.','7','.','1','8','.','4','2',
'4','5','1','.','.','.','.','8','3'
};
printf("Testing isLegal() function ............\n");
result = TRUE;
solution = hasSolution(testGrid);
showGame(testGrid);
int f = isLegal(testGrid,78,'9');
printf("isLegal(testGrid,78,9) = %d\n\n",f);
i = 0;
result = TRUE;
value cellValue;
if (solution){
while ((result == TRUE) && (i < GRID_SIZE)){
cellValue = testGrid[i];
testGrid[i] = EMPTY_VALUE;
printf("isLegal(testGrid,%d,%c) = %d\n",i,cellValue,isLegal(testGrid,i,cellValue));
result = result && isLegal(testGrid,i,cellValue);
testGrid[i] = cellValue;
i++;
}
}
if (result)
printf("\t\t\t\t\t [OK]\n");
else
printf("\t\t\t\t\t[NOK]\n");
}
The result of executing this function with a wrong result is: 执行此函数的结果是错误的:
6 4 2 5 3 9 8 1 7
1 7 5 8 6 2 2 3 4
9 3 8 1 4 7 5 9 6
2 8 3 7 9 6 1 7 5
5 6 4 3 8 1 3 2 8
7 1 9 2 5 4 4 6 9
8 2 6 4 2 3 6 5 1
3 9 7 6 1 8 7 4 2
4 5 1 9 7 5 9 8 3
There are many mistakes here but I mentioned the both 9-s in the last line (possitions 75 and 78). 这里有很多错误,但我在最后一行(位置75和78)中提到了两个9-s。 Performed a manual check for isLegal(testGrid,78,'9') which returns FALSE, but when I use a loop isLegal(testGrid,i,cellValue) returns TRUE all the time:
对isLegal(testGrid,78,'9')执行了手动检查,该检查返回FALSE,但是当我使用循环时,isLegal(testGrid,i,cellValue)始终返回TRUE:
isLegal(testGrid,78,9) = 0
isLegal(testGrid,0,6) = 1
isLegal(testGrid,1,4) = 1
isLegal(testGrid,2,2) = 1
isLegal(testGrid,3,5) = 1
.....
isLegal(testGrid,78,9) = 1
isLegal(testGrid,79,8) = 1
isLegal(testGrid,80,3) = 1
My question is why when I use char variable in ' ' quotes (isLegal(testGrid,78,'9') from the code) it shows the correct result, but not when I use cellValue variable? 我的问题是为什么当我在''引号(代码中的isLegal(testGrid,78,'9'))中使用char变量时,它显示正确的结果,但是当我使用cellValue变量时却没有? How can this be fixed?
如何解决?
Thank you! 谢谢!
Adding additional information: 添加其他信息:
#define MIN_VALUE '1'
#define MAX_VALUE '9'
#define EMPTY_VALUE '.'
#define NUM_VALUES (MAX_VALUE - MIN_VALUE + 1)
#define GRID_SIZE (NUM_VALUES * NUM_VALUES)
#define MAX_CELL (GRID_SIZE - 1)
#define TRUE 1
#define FALSE 0
#define MINI_SQUARE_SIZE 3
#define SQUARE_SIZE 9
typedef int cell;
typedef char value;
typedef value sudokuGrid[GRID_SIZE];
isLegal function: isLegal函数:
int isLegal (sudokuGrid game, cell location,value candidateDigit){
assert (location >= 0);
assert (location <= GRID_SIZE);
assert (candidateDigit >= MIN_VALUE);
assert (candidateDigit <= MAX_VALUE);
return (isLegalLine(game,location,candidateDigit) &&
isLegalColumn(game,location,candidateDigit) &&
isLegalSquare(game,location,candidateDigit));
}
static int isLegalLine(sudokuGrid game, cell location,value candidateDigit){
assert (location >= 0);
assert (location <= GRID_SIZE);
assert (candidateDigit >= MIN_VALUE);
assert (candidateDigit <= MAX_VALUE);
int result, mid_result;
int i;
int lineNumber = location / SQUARE_SIZE;
result = TRUE;
for (i = 0; i < GRID_SIZE; i++){
if (( i / SQUARE_SIZE ) == lineNumber){
if ( game[i] != candidateDigit ){
mid_result = TRUE;
}
else{
mid_result = FALSE;
}
result = result && mid_result;
}
}
return result;
}
static int isLegalColumn(sudokuGrid game, cell location,value candidateDigit){
assert (location >= 0);
assert (location <= GRID_SIZE);
assert (candidateDigit >= MIN_VALUE);
assert (candidateDigit <= MAX_VALUE);
int result, mid_result;
int i;
int columnNumber = location % SQUARE_SIZE;
result = TRUE;
for (i = 0; i < GRID_SIZE; i++){
if (( i % SQUARE_SIZE ) == columnNumber){
if ( game[i] != candidateDigit )
mid_result = TRUE;
else
mid_result = FALSE;
result = result && mid_result;
}
}
return result;
}
static int isLegalSquare(sudokuGrid game, cell location,value candidateDigit){
assert (location >= 0);
assert (location <= GRID_SIZE);
assert (candidateDigit >= MIN_VALUE);
assert (candidateDigit <= MAX_VALUE);
int result, mid_result;
int i;
int lineNumber = location / SQUARE_SIZE;
int columnNumber = location % SQUARE_SIZE;
// int squareNumber;
if ( lineNumber < MINI_SQUARE_SIZE){
lineNumber = 0;
if (columnNumber < MINI_SQUARE_SIZE){
// squareNumber = 1;
columnNumber = 0;
}
else if (columnNumber < 2*MINI_SQUARE_SIZE){
// squareNumber = 2;
columnNumber = MINI_SQUARE_SIZE;
}
else{
// squareNumber = 3;
columnNumber = 2*MINI_SQUARE_SIZE;
}
}
else if (lineNumber < 2*MINI_SQUARE_SIZE){
lineNumber = MINI_SQUARE_SIZE;
if (columnNumber < MINI_SQUARE_SIZE){
// squareNumber = 4;
columnNumber = 0;
}
else if (columnNumber < 2*MINI_SQUARE_SIZE){
// squareNumber = 5;
columnNumber = MINI_SQUARE_SIZE;
}
else{
// squareNumber = 6;
columnNumber = 2*MINI_SQUARE_SIZE;
}
}
else{
lineNumber = 2*MINI_SQUARE_SIZE;
if (columnNumber < MINI_SQUARE_SIZE){
// squareNumber = 7;
columnNumber = 0;
}
else if (columnNumber < 2*MINI_SQUARE_SIZE){
// squareNumber = 8;
columnNumber = MINI_SQUARE_SIZE;
}
else{
// squareNumber = 9;
columnNumber = 2*MINI_SQUARE_SIZE;
}
}
result = TRUE;
int squareStartLocation = columnNumber + ( SQUARE_SIZE * lineNumber);
int k = 0;
int squareStartLocationLineEnd;
while (k < MINI_SQUARE_SIZE){
squareStartLocationLineEnd = squareStartLocation + MINI_SQUARE_SIZE;
for (i = squareStartLocation; i < squareStartLocationLineEnd; i++){
if (game[i] != candidateDigit)
mid_result = TRUE;
else
mid_result = FALSE;
result = result && mid_result;
}
k++;
squareStartLocation += SQUARE_SIZE;
result = result && mid_result;
}
return result;
}
Think a little bit about what this: 想一想这是什么:
testGrid[i] = EMPTY_VALUE;
will do to isLegal() in the next line: 在下一行将对isLegal()进行操作:
printf("isLegal(testGrid,%d,%c) = %d\n",i,cellValue,isLegal(testGrid,i,cellValue));
Maybe this does something in isLegal() what you don't want 也许这在isLegal()中做了一些您不想要的事情
Parameter candidateDigit will be passed as a char type to isLegal(). 参数候选人候选者将作为char类型传递给isLegal()。 It must be the loop context causing the function to always return TRUE, so you will need to:
它必须是导致函数始终返回TRUE的循环上下文,因此您将需要:
Update1: Thanks for the extra info. 更新1:感谢您的额外信息。 I plugged in your filled out "bad" data, set solution to TRUE, and the test stopped at position 14 with a failure (correctly as this position contains '2' and there is another in the same line).
我插入了您填写的“错误”数据,将解决方案设置为TRUE,并且测试在第14位失败并失败了(正确的原因是该位置包含“ 2”,并且同一行中还有另一个)。 So it seems that your code is correct!
因此,看来您的代码是正确的! At least as far as this test goes.
至少就此测试而言。
Test grid: 测试网格:
sudokuGrid testGrid = {
'6','4','2','5','3','9','8','1','7',
'1','7','5','8','6','2','2','3','4',
'9','3','8','1','4','7','5','9','6',
'2','8','3','7','9','6','1','7','5',
'5','6','4','3','8','1','3','2','8',
'7','1','9','2','5','4','4','6','9',
'8','2','6','4','2','3','6','5','1',
'3','9','7','6','1','8','7','4','2',
'4','5','1','9','7','5','9','8','3'
};
Test output: 测试输出:
isLegal(testGrid,78,9) = 0
isLegal(testGrid,0,6) = 1
isLegal(testGrid,1,4) = 1
isLegal(testGrid,2,2) = 1
isLegal(testGrid,3,5) = 1
isLegal(testGrid,4,3) = 1
isLegal(testGrid,5,9) = 1
isLegal(testGrid,6,8) = 1
isLegal(testGrid,7,1) = 1
isLegal(testGrid,8,7) = 1
isLegal(testGrid,9,1) = 1
isLegal(testGrid,10,7) = 1
isLegal(testGrid,11,5) = 1
isLegal(testGrid,12,8) = 1
isLegal(testGrid,13,6) = 1
isLegal(testGrid,14,2) = 0
[NOK]
NB Only other code changes I made were to move isLegal() below the functions that it calls (to avoid default promotion of return types) and to comment out calls to hasSolution() and showGrid(). 注意:我所做的其他代码更改仅是将isLegal()移到其调用的函数下方(以避免默认提升返回类型),并注释掉对hasSolution()和showGrid()的调用。
If you do char a = 9
, you are making that a
have an ASCII value. 如果执行
char a = 9
,则使a
具有ASCII值。 For example: char letter = 80;
例如:
char letter = 80;
is equivalent to char letter = 'P';
等价于
char letter = 'P';
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