Perl字符串替换：匹配但不替换正则表达式的一部分

Question

Say I have a string in Perl I am trying to match and replace with stuff:

$string =~ s/[^a-zA-Z]$find[^a-zA-Z]/$replace/g;

So as shown, I want to replace everything that is surrounded on both sides by nonletter characters. However, when I replace the string, I do NOT want to also replace these characters: they are just necessary for correct matching. How can I tell the Perl regex to avoid replacing the things surrounding $find ?

Answer 1

将它们存储为匹配的组，并在替换字符串中引用它们：

$string =~ s/([^a-z])$find([^A-Z])/\1$replace\2/gi;

Answer 2

使用环顾断言 。

s/(?<=[^a-zA-Z])$find(?=[^a-zA-Z])/$replace/g