具有记忆的C样式转换

Question

Here is an example of a C-Style cast that I am using:

*(char*)(0x0FCA41E + (0x280 * i)) = 0xFF;

This code is essentially a Call of Duty hack which tampers with the health of the player. By default, the value at address 0x0FCA41E is 0x00 but changing it to 0xFF initiates infinate health. I understand what this line of code does, but does this have to be a char ? Can it look like this?

*(int*)(0x0FCA41E + (0x280 * i)) = 0xFF;
//or
*(short*)(0x0FCA41E + (0x280 * i)) = 0xFF;

I understand that 0xFF is one byte of memory, like a char , but what would happen if I used an int or a short ? Would that work?

If not, then what would be an example of using an int or short in this sense?

Thanks!

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By the way, I made a similar post to this a few days go (incase it looks familiar) but this is a different question overall.

Answer 1

In addition to what iharob said, another difference is how much memory the assignment will overwrite. In the example, using a char will overwrite a single byte with 0xFF. But if you cast it to an int, then 4 or 8 bytes (depending on the machine architecture) will be overwritten. This will result in some undefined behavior as you don't know what other values, if any, will be erased.