使用变量操作 bash 脚本输出

Question

I am new to scripting using Linux. When running a script I want to be selective about what output the script show from a command, instead of displaying all of a commands output, I would like for it to display some of its words or sentences. How do I do that. Help will be appreciated. See below.

#!/bin/bash
#

megacliout=$(sudo megacli -AdpAutoRbld -Dsply -a0)

echo $megacliout | cut -d '0' -f 2

The output I get is:

: AutoRebuild is Enabled. Exit Code: 

But I do not want 'Exit Code:' to be displayed in the output. So how do I remove that and keep everything else?

Answer 1

This question is likely better answered at SuperUser.

That said, your cut command is unlikely to work reliably. You are using it to extract text between two zeroes (which might or might not be present in the output).

As an alternative, you can try grep , for example like so: grep -o 'AutoRebuild is [^.]*' This will output only phrases that start with "AutoRebuild is", continuing until the next dot.

Answer 2

您可以使用sed删除“退出代码”及其后的所有内容：

echo "$megacliout" | cut -d0 -f2 | sed 's/ Exit Code.*$//'