在Bash脚本变量中使用命令

Question

I have a bash script which checks the current status of Dropbox

#!/bin/bash
while true
do
    echo Dropbox Status: 
    ~/bin/dropbox.py status
    sleep 1
    clear
done

This produces a output which can look like this.

Dropbox Status: 
Up to date

However I would like it to look like this. So it is all on one line

Dropbox Status: Update

I have tried scripts such as

#!/bin/bash
while true
do
    STATUS=~/bin/dropbox.py status
    echo Dropbox Status: $STATUS
    sleep 1
    clear
done

However this just creates errors such as Dropbox Status.sh: status: not found

Is there a way to do what I am after?

Also if it is blatantly obvious I apologize since I am new to Bash Script

Thanks for any help.

Answer 1

您需要将命令结果存储在状态var中

  STATUS=$(~/bin/dropbox.py status)

Answer 2

Use printf and command substitution :

printf "Dropbox Status: %s\n" "$(~/bin/dropbox.py status)"

or with intermediate variable:

status=$(~/bin/dropbox.py status)
printf "Dropbox Status: %s\n" "$status"

Also remember to quote your variables or they will undergo word splitting

Why doesn't STATUS=~/bin/dropbox.py status work? Whats happens is that the command status is called with the environment variable STATUS set to ~/bin/dropbox.py , sort of the same as running:

_status=$STATUS
export STATUS=~/bin/dropbox.py
status
export STATUS=_status

But without all the temporary variables