[英]Searching for key in dictionary, and printing the key and its value
I am trying to search for the key in the dictionary of songs. 我正在尝试在歌曲字典中搜索键。 They keys are the song titles, and the value is the length of the song.
它们的键是歌曲标题,而值是歌曲的长度。 I want to search for the song in the dictionary, and then print out that song and its time.
我想在字典中搜索歌曲,然后打印出该歌曲及其时间。 I have figured out searching for the song, but can't remember how to bring out its value as well.
我已经想出了寻找这首歌的方法,但是想不起来如何发挥它的价值。 Here is what I currently have.
这是我目前拥有的。
def getSongTime(songDictionary):
requestedSong=input("Enter song from playlist: ")
for song in list(songDictionary.keys()):
if requestedSong in songDictionary.keys():
print(requestedSong,value)
There'no need to iterate through the dictionary keys - quick lookup is one of the main reasons for using a dictionary instead of a tuple or list. 无需遍历字典键-快速查找是使用字典而不是元组或列表的主要原因之一。
With a try/except: 尝试/除外:
def getSongTime(songDictionary):
requestedSong=input("Enter song from playlist: ")
try:
print(requestedSong, songDictionary[requestedSong])
except KeyError:
print("Not found")
With the dict's get
method: 使用dict的
get
方法:
def getSongTime(songDictionary):
requestedSong=input("Enter song from playlist: ")
print(requestedSong, songDictionary.get(requestedSong, "Not found"))
I don't think using try catch is good for this task. 我认为使用try catch不适合完成此任务。 Simply use the operator
in
只需
in
requestedSong=input("Enter song from playlist: ")
if requestedSong in songDictionary:
print songDictionary[requestedSong]
else:
print 'song not found'
And I strongly recommend you to read this article http://www.tutorialspoint.com/python/python_dictionary.htm 我强烈建议您阅读这篇文章http://www.tutorialspoint.com/python/python_dictionary.htm
Also check out this questions too: check if a given key exists in dictionary 也要检查一下这个问题: 检查字典中是否存在给定的键
try vs if 尝试vs如果
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