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在字符串中查找列表的确切项目

[英]Find exact item of list in a string

I have a problem of false negative during a loop in python. 我在python循环期间遇到假阴性的问题。

That's my list: 那是我的清单:

l = ['modello', 'modello1', 'modello_old', 'new_modello']

and that's a string: 那是一个字符串:

db = '/home/user/modello1.sqlite'

What I want to do is to filter the db string and to output the element of the list that appear in the string. 我想做的是过滤db字符串并输出出现在字符串中的列表元素。

So the result should be only modello1 . 因此,结果应仅为 modello1

This is my loop: 这是我的循环:

for i in l:
    if i in db:
        print i

but the result is not what I would like to obtain: 但结果不是我想要获得的:

modello
modello1

how can I match the exact word? 如何匹配确切的单词?

EDIT : the problem could be that db is OS dependent so / could be transformed in \\ . 编辑 :问题可能是db依赖于操作系统,所以/可以在\\进行转换。

EDIT2 : with @Karoly-Horvath solution: EDIT2 :使用@ Karoly-Horvath解决方案:

transform the db in a list: 转换列表中的数据库:

db = [os.path.basename(db).replace('.sqlite', '')]

loop the element of db in the whole list: 在整个列表中循环db的元素:

for i in db:
    if i in l:
        print i

Use a regular expression or string functions to extract the relevant part: 使用正则表达式或字符串函数提取相关部分:

m = os.path.basename(db).replace('.sqlite', '')  # 'modello1'

or (this was the original answer, only works for unix paths) 或(这是原始答案,仅适用于Unix路径)

m = db.split('/')[-1].replace('.sqlite', '')     # 'modello1'

Now you can check for an exact match: 现在您可以检查完全匹配:

m in l   # True

If you want to check against the filename without the extension, use os.path.basename and os.path.splitext : 如果要检查不带扩展名的文件名,请使用os.path.basenameos.path.splitext

>>> from os import path
>>> s = '/home/user/modello1.sqlite'

>>> path.basename(s)
>>> 'modello1.sqlite'

>>> path.splitext(path.basename(s))
('modello1', '.sqlite')

>>> filename = path.splitext(path.basename(s))[0]
>>> filename
'modello1'

Using the filename: 使用文件名:

>>> possibles = ['modello', 'modello1', 'modello_old', 'new_modello']
>>> for possible in possibles:
...     if possible in filename:
...         print possible, 'in', filename
modello in modello1
modello1 in modello1

If you just want to check whether any of the possibilities match: 如果您只想检查是否有任何可能性匹配:

>>> if any(possible in filename for possible in possibles):
...     print filename
modello1

I think I understand now that OP would want an exact match: 我想我现在知道OP想要一个完全匹配的东西:

>>> if filename in possibles:
...     print filename
modello1

This won't match modello . 这与modello不匹配。

import os
db_basename = os.path.basename(db)
db_basename = os.path.splitext(db_basename)[0] # remove extension

use os to get file name 使用os获取文件名

How about this 这个怎么样

for i in l:
    if '/'+i+'.' in db:
        print i

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