从数组中删除虚假值会使我留空值。 如何改善我的代码？

Question

I'm trying to remove the falsy values from an array. I tried usign typeOf and Boolean, but that would leave me with null values inside my array. How can I improve my code?

function bouncer(arr) {
    var myarr=[];
    for(var i=0;i<arr.length;i++)
    {
        if(typeof arr[i] === 'boolean' || arr[i]=== 0 || arr[i]==="")
        {
            delete arr[i];
        }

    }
    return arr;
}

bouncer([7, "ate", "", false, 9]);

The outout from this code:

([7, "ate", null, null, 9])

How can I improve this code ? Why does typeOf ==='boolean' not delete 0 and null string "".

Update: The code should satisfy the below criteria.

bouncer([7, "ate", "", false, 9]) should return [7, "ate", 9].
bouncer(["a", "b", "c"]) should return ["a", "b", "c"].
bouncer([false, null, 0, NaN, undefined, ""]) should return [].

Thank you

Answer 1

Could it be as simple as this?

 var arr = [7, "ate", "", false, 9, "a", "b", "c", false, null, 0, NaN, undefined, ""]; var result = arr.filter(a=>a); // [7, "ate", 9, "a", "b", "c"] console.log(document.body.innerHTML = result); 

Answer 2

var newArr = [];
arr.forEach(function(element) {
    if (element != false)
        newArr.push(element);
});
return newArr;

Answer 3

尝试是否（！arr [i]）{arr.splice（i，1）}