[英]Extended sequence unpacking in python3
I create a list as: 我创建一个列表:
>>> seq = [1, 2, 3, 4]
Now i assign the variables as follows: 现在我分配变量如下:
>>> a, b, c, d, *e = seq
>>> print(a, b, c, d, e)
I get output as: 我输出为:
>>> 1 2 3 4 []
Now i change the sequence in which i assign variables as: 现在我改变我将变量赋值为的顺序:
>>> a, b, *e, c, d = seq
>>> print(a, b, c, d, e)
I get output as: 我输出为:
>>> 1, 2, 3, 4, []
So my question is Why *e variable above is always assigned an empty list regardless of where it appears? 所以我的问题是为什么*上面的变量总是被分配一个空列表而不管它出现在哪里?
In the first case 在第一种情况下
a, b, c, d, *e = seq
since the sequence has only four elements, a
, b
, c
and d
get all of them and the rest of them will be stored in e
. 由于序列只有四个元素,
a
, b
, c
和d
得到所有元素,其余的将存储在e
。 As nothing is left in the sequence, e
is an empty list. 由于序列中没有任何内容,
e
是一个空列表。
In the second case, 在第二种情况下,
a, b, *e, c, d = seq
First two elements will be assigned to a
and b
respectively. 前两个元素将分别分配给
a
和b
。 But then we have two elements after the *e
. 但是在
*e
之后我们有两个元素。 So, the last two elements will be assigned to them. 因此,最后两个元素将分配给它们。 Now, there is nothing left in the
seq
. 现在,
seq
没有任何东西了。 That is why it again gets an empty list. 这就是为什么它再次得到一个空列表。
It was a design choice, according to PEP 3132 (with my bold): 根据PEP 3132 (我的大胆),这是一个设计选择:
A tuple (or list) on the left side of a simple assignment (unpacking is not defined for augmented assignment) may contain at most one expression prepended with a single asterisk (which is henceforth called a "starred" expression, while the other expressions in the list are called "mandatory").
简单赋值左侧的元组(或列表)(未为扩充赋值定义解包)最多可包含一个前缀为单个星号的表达式(此后称为“已加星标”的表达式,而其他表达式则为该列表被称为“强制”)。 This designates a subexpression that will be assigned a list of all items from the iterable being unpacked that are not assigned to any of the mandatory expressions , or an empty list if there are no such items.
这指定一个子表达式,该子表达式将被分配一个列表, 其中包含未被分配给任何强制性表达式的可迭代迭代的所有项目,或者如果没有这样的项目,则为空列表。
Indeed, the first example in the PEP illustrates your point: 实际上,PEP中的第一个例子说明了你的观点:
>>> a, *b, c = range(5)
>>> a
0
>>> c
4
>>> b
[1, 2, 3]
a, b, *e, c, d = [1, 2, 3, 4]
*e
says "what's left put into e
". *e
说:“还剩下些什么投入e
”。 Because you have 4 elements, empty sequence is put into e
. 因为你有4个元素,所以将空序列放入
e
。
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