获取仅包含少于4位数字的行

Question

I need to fetch the rows that contain less than 4 consecutive digits. 我需要获取少于4个连续数字的行。 I tried using this : 我尝试使用这个：

select mycolumn where mycolumn REGEXP '[0-9]{1,3}'

but this still returned rows such as "Test Text 1234-1234" I need to return these only: 但这仍返回诸如"Test Text 1234-1234"行，我只需要返回这些行：

Test 12
Test 234 Text
Test /2 Text
text 123 text 1234 text

Answer 1

Thanks to @BenM and @lad2025, the correct answer is: 感谢@BenM和@ lad2025，正确的答案是：

'[[:<:]][0-9]{1,3}[[:>:]]'