Mysql-在一个输出中合并来自两个不同数据库的两个选择查询
[英]Mysql - Combine two select queries, from two different databases in just one output
问题描述
I am quite new to SQL stuff, and I am in situation where I don't have enough knowledge to achieve the following. 
我对SQL知识还很陌生，而且我所处的知识不足以实现以下目标。
I am trying to combine the results of two select queries, but one query is from one data base and one for another . 我试图合并两个选择查询的结果，但是一个查询来自一个数据库，另一个来自另一个数据库。 Both data bases are in the same server. 两个数据库都在同一服务器上。
Like below : 像下面这样：
On Database1 I run the query below : 在Database1上，我运行以下查询：
MariaDB [(none)]> select GENRE,STYLE,CONTENT_ID,PROMO_END_DATE from Database1.PROMOTION_LIST ;
+-----------+---------------------------------------+-------------------------+----------------------+
| GENRE | STYLE | CONTENT_ID |PROMO_END_DATE |
+-----------+---------------------------------------+-------------------------+----------------------+
| ROCK |Hard Rock,Opera Rock, Syphonic Rock | 11111,22222,33333 | 2015-12-02 04:00:00 |
| METAL |Black Metal, Death Metal, Heavy Metal | 55555,66666,77777,22222 | 2015-12-29 11:00:00 |
| ELECTRO |Dance, Tance, Flash House | 88888,22222,66666,44444 | 2015-12-02 07:00:00 |
+-----------+-------------+---------------------------------------------------+----------------------+
On Database2 I run the query below : 在Database2上，我运行以下查询：
SELECT SONG_ID,SONG_NAME,ARTIST FROM Database2.song_master_table
+---------+---------------+---------+
| SONG_ID | SONG_NAME | ARTIST |
+---------+---------------+---------+
| 11111 | SONG1 | BAND1 |
| 22222 | SONG2 | SINGER1 |
| 33333 | SONG3 | ARTIST1 |
| 44444 | SONG4 | BAND2 |
| 55555 | SONG5 | SINGER2 |
| 66666 | SONG6 | ARTIST2 |
| 77777 | SONG7 | BAND2 |
| 88888 | SONG8 | SINGER2 |
+---------+---------------+---------+
And the output I am trying to achieve is : 我想要实现的输出是：
+-----------+---------------------------------------+-------------------------+--------------+---------------+--------------------+
| GENRE | STYLE | CONTENT_ID | ARTIST | SONG_NAME | PROMO_END_DATE |
+-----------+---------------------------------------+-------------------------+--------------+---------------+--------------------+
| ROCK |Hard Rock,Opera Rock, Syphonic Rock | 11111 | BAND1 | SONG1 | 2015-12-02 04:00:0 |
| | | 22222 | SINGER1 | SONG2 | 2015-12-02 04:00:0 |
| | | 33333 | ARTIST1 | SONG3 | 2015-12-02 04:00:0 |
| METAL |Black Metal, Death Metal, Heavy Metal | 55555 | SINGER2 | SONG5 | 2015-12-02 04:00:0 |
| | | 66666 | ARTIST2 | SONG6 | 2015-12-02 04:00:0 |
| | | 77777 | BAND2 | SONG7 | 2015-12-02 04:00:0 |
| | | 22222 | SINGER1 | SONG2 | 2015-12-02 04:00:0 |
| | | 33333 | ARTIST1 | SONG3 | 2015-12-02 04:00:0 |
| ELECTRO |Dance, Tance, Flash House | 88888 | SINGER2 | SONG8 | 2015-12-02 04:00:0 |
| | | 22222 | SINGER1 | SONG2 | 2015-12-02 04:00:0 |
| | | 66666 | ARTIST2 | SONG6 | 2015-12-02 04:00:0 |
| | | 44444 | BAND2 | SONG4 | 2015-12-02 04:00:0 |
+-----------+---------------------------------------+-------------------------+--------------+---------------+--------------------+
I tried to use join and union, but the syntax were not correct. 我尝试使用连接和联合，但是语法不正确。
Consider that : 考虑到：
Database1,CONTENT_ID and Database2 SONG_ID are the same info. Database1，CONTENT_ID和Database2 SONG_ID是相同的信息。 And I am not sure if possible, but the output will need to group the artist / song_name as per CONTENT_ID table. 而且我不确定是否可以，但是输出将需要根据CONTENT_ID表将歌手/歌曲名分组。 And there is no where condition. 而且没有条件。
I appreciate all and any help. 我感谢所有帮助。
Thanks in advanced. 提前致谢。
1 个解决方案
解决方案1
0 2015-11-30 17:46:24
Add column id to Database1.PROMOTION_LIST then create another table which will connect this id with SONG_ID : 将列id添加到Database1.PROMOTION_LIST然后创建另一个表，该表将将该id与SONG_ID连接：
promo_id song_id
1 11111
1 22222
1 33333
2 55555
...
Then it will be much easier to create the query you need. 然后，创建所需的查询会容易得多。
Let me know if you need further help. 让我知道您是否需要进一步的帮助。
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