使用UPDATE（mysql）将数据库递增1。 我的代码有什么问题？
[英]Increment database by 1, using UPDATE (mysql). What's wrong with my code?
问题描述
I try to write code that receive a student ID as an input in student_list.php, and pass this ID to score.php. 
我尝试编写代码以在student_list.php中接收输入的学生ID，并将该ID传递给score.php。
At score.php, use that ID to match and pull out student's name from database, and display it here. 在score.php中，使用该ID进行匹配以从数据库中提取学生的姓名，并在此处显示它。
Then, below the name, there is an input field, for adding 1 score to database for this student. 然后，在名称下方，有一个输入字段，用于为该学生的数据库添加1分。
But I got this message, "You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 1". 但是我收到此消息，“您的SQL语法有误；请查看与您的MySQL服务器版本相对应的手册，以找到在第1行的''附近使用正确的语法”。
Any help would be appreciated. 任何帮助，将不胜感激。 Thank you. 谢谢。
student_list.php student_list.php
<?php include_once 'DBconnect.php'; ?> <html> <head>Student List</head> <body> <form method="post" action="score.php"> <?php $result = mysql_query("SELECT * FROM term3") or die(mysql_error()); echo "<table border='1'>"; echo "<tr> <th>Student ID</th> <th>First Name</th> <th> Button </th> </tr>"; while($row = mysql_fetch_array( $result )) { echo "<tr>"; echo '<td>' . $row['student_id'] . ' </td> '; echo '<td>' . $row['student_fname'] . ' </td>'; echo '<td> <button type="submit" name="btn_student_id" value=" ' . $row['student_id'] . ' " >Select</button> </td>'; echo '</tr>'; } echo "</table>"; ?> </form> </body> </html>
score.php score.php
<?php include_once 'database_connect.php'; ?> <html> <head>Add Score</head> <body> <?php $student_id = $_POST["btn_student_id"]; $result = mysql_query("SELECT * FROM term3 WHERE student_id=".$_POST['btn_student_id']) or die(mysql_error()); echo "<table border='1'>"; echo "<tr> <th>Student ID</th> <th>First Name</th> </tr>"; while($row = mysql_fetch_array( $result )) { echo "<tr>"; echo '<td>' . $row['student_id'] . ' </td> '; echo '<td>' . $row['student_fname'] . ' </td>'; echo '</tr>'; } echo "</table>"; if(isset($_POST['btn_add_score'])) { $score = $_POST['score']; mysql_query ("UPDATE term3 SET score = score + 1 WHERE student_id = ' ".$_POST['btn_student_id']. " ' "); } ?> <form method="post"> <table> <tr> <td>Score</td> <td> <input type="number" name="score" size="8"> <button type="submit" name="btn_add_score" >Add</button> </td> </tr> </table> </form> </body> </html>
---------------------------------------- Student ID | Name | Select | ---------------------------------------- 10001 | Pat | Button (submit) | ---------------------------------------- 10002 | Jess | Button (submit) | ----------------------------------------
2 个解决方案
解决方案1
0 2015-11-29 20:55:40
Try to remove the quotation marks around the student id in the update query. 尝试删除更新查询中学生ID周围的引号。 It is redundant 这是多余的
UPDATE term3 SET score = score + 1 WHERE student_id = ".$_POST['btn_student_id']);
解决方案2
-4 2015-11-29 20:52:13
Update 更新资料
$result = mysql_query("SELECT * FROM term3 WHERE student_id=".$_POST['btn_student_id'])
to 至
$result = mysql_query("SELECT * FROM term3 WHERE student_id='".$_POST['btn_student_id']."'")
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