使用prepare从数据库检索数据的我的代码有什么问题

Question

this is my php code for retrieving data from database using prepare statement

if ($conn) { //database connected success

$view_sql = "SELECT * FROM certificate_verify";
$stmt_view = $conn->prepare($view_sql);
$stmt_view->execute();

$results_view = $stmt_view->fetchAll();

foreach($results_view as $row) {

    $view_first_name = $row['first_name'];
    $view_last_name = $row['last_name'];
}

I need to fetch all data from database to display in the following display page

<table>
  <tr>
    <td><?php echo $view_first_name; ?></td>
    <td><?php echo $view_last_name; ?></td>
  </tr>
</table>

but I am getting only last row data (not all data from database) why it is happening and what is wrong with my code?

Answer 1

Use foreach loop inside your table as otherwise you data ovetlap inside foreach loop and you get only last value

<?php
$results_view = $stmt_view->fetchAll();
?>
<table>
    <?php foreach ($results_view as $row) { ?>// start your loop here
        <tr>
            <td><?php echo $row['first_name']; ?></td>
            <td><?php echo $row['last_name']; ?></td>
        </tr>
    <?php } ?>// loop end
</table>

Answer 2

replace your foreach(...){...} code with this:

echo "<table>";
foreach ($results_view as $row)
{
  echo "<tr>";
  foreach ($row as $cell)
  {
    echo "<td>".$cell."</td>";
  }
  echo "</tr>";
}
echo "</table>";

Answer 3

Obviously, Because every time you iterate your foreach loop, your $view_first_name and $view_last_name get overwritten with new values coming from $row . You need to make $view_first_name and $view_last_name Array and iterate those over tr .