SQL Server 2005：通过比较两个值来更新状态列

Question

I have a table where I have to check the values between column Value1 and value2 . If value1 is less than value2 , update the status 'Low' in Status column, if greater then update status to 'High'.

Table Screenshot

I have tried with this query

UPDATE table 
SET Status = If(value1 <= value2) Then 'Low' else 'High'

Please guide to a solution.

Answer 1

This will work

UPDATE TABLE
SET Status =
CASE WHEN (value1 <= value2) THEN 'Low'
ELSE 'High' END