[英]Two Dimensional Array: C Programming
Can anyone help, I am stuck on solving this question:谁能帮忙,我一直在解决这个问题:
Write a function in C that takes three parameters: the address of a two dimensional array of type
int
, the number of rows in the array, and the number of columns in the array.用 C 编写一个函数,它接受三个参数:
int
类型的二维数组的地址、数组中的行数和数组中的列数。 Have the function calculate the sum of the squares of the elements.让函数计算元素的平方和。
For example, for the array of nums
that is pictured below:例如,对于下图所示的
nums
数组:
23 12 14 3
31 25 41 17
the call of the function might be sumsquares ( nums, 2, 4 )
;函数的调用可能是
sumsquares ( nums, 2, 4 )
; and the value returned would be 4434
.并且返回的值将是
4434
。 Write a short program to test your function.编写一个简短的程序来测试您的功能。
So far my program consists of:到目前为止,我的程序包括:
#include<stdio.h>
int addarrayA(int arrayA[],int highestvalueA);
int addarrayA(int arrayA[],int highestvalueA)
{
int sum=0, i;
for (i=1; i<highestvalueA; i++)
sum = (i*i);
return sum;
}
int main( void )
{
int arr [2][4] = {{ 23, 12, 14, 3 },
{ 31, 25, 41, 17 }};
printf( "The sum of the squares: %d. \n", addarrayA (arr[2], arr[4]) );
return 0;
}
The answer I am receiving is a huge negative number but it should be 4434.我收到的答案是一个巨大的负数,但应该是 4434。
Any help is greatly appreciated!任何帮助是极大的赞赏!
As you mentioned in question, you need sumsquares( array, 2, 4 );
正如您在问题中提到的,您需要
sumsquares( array, 2, 4 );
, but your function don't do that. ,但您的功能不这样做。
See below code:见下面的代码:
#include<stdio.h>
int sumsquares(int* arrayA,int row, int column);
int sumsquares(int* arrayA,int row, int column)
{
int sum=0, i;
for (i=0; i<row*column; i++)
sum += (arrayA[i]*arrayA[i]);
return sum;
}
int main( void )
{
int arr [2][4] = {{ 23, 12, 14, 3 },
{ 31, 25, 41, 17 }};
printf( "The sum of the squares: %d. \n", sumsquares (&arr[0][0], 2, 4) );
return 0;
}
Output :
输出:
The sum of the squares: 4434.
我们可以使用这个语法在 C 中创建一个多维数组:
arr = (int **) malloc (( n *sizeof(int *));
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