[英]Display contents of a string in html table using preg_match and regex
I have a string that contains ASL of users seprated by a pipe 我有一个字符串,其中包含由管道分隔的用户ASL
my string : 我的字符串:
Jack:22:m:london,uk|john:20:m:otava, canada|ketty:26:f:san fransisco|patricia:19:f:guatemala city
my regex : 我的正则表达式:
/([A-Za-z]+):([0-9]+):([A-Za-z]):([^|]+/
I want to display these asls on my wepage in html table. 我想在html表格的wepage上显示这些asls。
jack 22 m london,uk
john 20 m otava canada
my code: 我的代码:
$users="Jack:22:m:london,uk|john:20:m:otava, canada|ketty:26:f:san fransisco|patricia:19:f:guatemala city";
echo preg_replace('/([A-Za-z]+):([0-9]+):([A-Za-z]):([^|]+)/','<table border="1"><tr><td>$1</td><td>$2</td><td>$3</td><td>$4</td></tr></table>',$users);
It's working as expected but the pipe | 它按预期工作但是管道 is being included in output .
正在纳入产出。
You can see the live demo of my code on https://eval.in/480802 您可以在https://eval.in/480802上看到我的代码的现场演示
Is there something wrong with my regex? 我的正则表达式有问题吗?
When using preg_replace, your regex will not touch the |
使用preg_replace时,你的正则表达式不会触及
|
character at all, thus simply leaves it there. 角色,因此只是留在那里。 A simple solution is to consume a single
|
一个简单的解决方案是使用单个
|
character if it exists at the end of your current regex pattern: 字符,如果它存在于当前正则表达式模式的末尾:
/([A-Za-z]+):([0-9]+):([A-Za-z]):([^\\|]+)\\|?/
(the \\|?
was added at the end) /([A-Za-z]+):([0-9]+):([A-Za-z]):([^\\|]+)\\|?/
(添加\\|?
在末尾)
Remember that the |
请记住
|
character should be escaped too ( \\|
). 字符也应该被转义(
\\|
)。
If I were you I will simply replace pipes with </td></tr><tr><td>
and semi-colons with </td><td>
: 如果我是你,我会简单地替换管
</td></tr><tr><td>
和分号与</td><td>
:
$users="Jack:22:m:london,uk|john:20:m:otava, canada|ketty:26:f:san fransisco|patricia:19:f:guatemala city";
echo '<table border="1"><tr><td>'
. strtr($users, ['|'=>'</td></tr><tr><td>', ':'=>'</td><td>'])
. '</td></tr></table>';
(Note: I don't think you want a different table for each record, so I putted all in the same table with a row for each record). (注意:我认为你不希望每个记录都有一个不同的表,所以我把所有表放在同一个表中,每个记录都有一行)。
If your data only contains |
如果您的数据仅包含
|
as user separator, and :
as user details separator, you can just use 2 explode
s like this: 作为用户分隔符,并且
:
作为用户详细信息分隔符,您可以像这样使用2个explode
:
$users="Jack:22:m:london,uk|john:20:m:otava, canada|ketty:26:f:san fransisco|patricia:19:f:guatemala city";
$usr_arr = explode('|', $users);
foreach ($usr_arr as $usr)
{
$parts = explode(':', $usr);
echo '<table border="1"><tr><td>'.$parts[0].'</td><td>'.$parts[1].'</td><td>'.$parts[2].'</td><td>'.$parts[3].'</td></tr></table>'.PHP_EOL;
}
See IDEONE demo 请参阅IDEONE演示
Output: 输出:
<table border="1"><tr><td>Jack</td><td>22</td><td>m</td><td>london,uk</td></tr></table>
<table border="1"><tr><td>john</td><td>20</td><td>m</td><td>otava, canada</td></tr></table>
<table border="1"><tr><td>ketty</td><td>26</td><td>f</td><td>san fransisco</td></tr></table>
<table border="1"><tr><td>patricia</td><td>19</td><td>f</td><td>guatemala city</td></tr></table>
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