[英]Combine multiple select statement in one result table
I have two tables, one for sales and another for stock. 我有两张桌子,一张用于销售,另一张用于库存。 I want to select location id, item id, size id and sales qty from sales table, while I want just to select stock qty from stock table for the same location id and size id from sales table, like this:
我想从销售表中选择位置ID,物料ID,尺寸ID和销售数量,而我只想从库存表中选择与销售表中相同的位置ID和尺寸ID的库存数量,如下所示:
Sales table: 销售表:
------------------------------------
| loc_id | item_id | size_id | qty |
------------------------------------
| 5 | 11321 | 1 | 5 |
| 5 | 11321 | 2 | 8 |
| 5 | 11321 | 3 | 4 |
| 5 | 11321 | 2 | 1 |
Stock table: 库存表:
------------------------------------
| loc_id | item_id | size_id | qty |
------------------------------------
| 5 | 11321 | 1 | 3 |
| 5 | 11321 | 2 | 7 |
| 5 | 11321 | 3 | 9 |
So the result after select should be like this: 所以选择后的结果应该是这样的:
------------------------------------------------------
| loc_id | item_id | size_id | sales_qty | stock_qty |
------------------------------------------------------
| 5 | 11321 | 1 | 5 | 3 |
| 5 | 11321 | 2 | 9 | 7 |
| 5 | 11321 | 3 | 4 | 9 |
Here's what I tried to do: 这是我尝试做的事情:
SELECT SUM(T1.qty) AS `salesQty`, SUM(T2.qty) AS `stockQty`, T1.size_id,
T1.loc_id
FROM sales T1
INNER JOIN stock T2 ON T2.item_id = T1.item_id AND T2.size_id = T1.size_id
WHERE T1.item_id = '11321'
AND T1.size_id IN (1,2,3)
AND T1.loc_id IN (5)
GROUP BY T1.size_id, T1.loc_id
But stock qty always wrong! 但是库存数量总是错误的!
select
q1.loc_id
,q1.item_id
,q1.size_id
,sum(case when q1.Type='Sales' then q1.Qty else 0 end) as sales_qty
,sum(case when q1.Type='Stock' then q1.Qty else 0 end) as stock_qty
from (
select
T1.loc_id
,T1.item_id
,T1.size_id
,'Sales' as Type
,SUM(T1.qty) AS Qty
from sales T1
group by
T1.loc_id
,T1.item_id
,T1.size_id
union all
select
T2.loc_id
,T2.item_id
,T2.size_id
,'Stock' as Type
,SUM(T2.qty) AS Qty
from stock T2
group by
T2.loc_id
,T2.item_id
,T2.size_id) q1
group by
q1.loc_id
,q1.item_id
,q1.size_id
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