[英]Combine multiple queries against one table into multiple fields of one result set
ANSWER : Here's the final query built from @Michael 's answer: 答案 :这是根据@Michael的答案构建的最终查询:
SELECT
Emp_ID,
MAX(CASE WHEN Skill_ID = 'WLN' THEN (Rating > 0) END) AS `WLN`,
MAX(CASE WHEN Skill_ID = 'LOC' THEN (Rating > 0) END) AS `LOC`,
MAX(CASE WHEN Skill_ID = 'BRV' THEN (Rating > 0) END) AS `BRV`,
AVG(CASE WHEN Skill_ID IN ('KWH','SIC','DOL') THEN (Rating) END) > 0 AS `KSD`
FROM Emp_Skill
WHERE Emp_ID IN (120,348,361,370)
GROUP BY Emp_ID
QUESTION : 问题 :
I have the following Emp_Skill
table: 我有以下
Emp_Skill
表:
Skill_ID* Emp_ID* Rating
--------------------------
WLN 120 6
WLN 348 5
WLN 361 7
WLN 370 8
LOC 120 7
LOC 370 7
LOC 348 7
BRV 120 3
LOC 361 6
BRV 348 1
KWH 348 5
KWH 120 5
KWH 361 5
KWH 370 5
SIC 361 8
SIC 348 4
SIC 120 2
DOL 348 5
DOL 361 8
and I need to know if an arbitrary number of employees have a positive skill rating for each skill . 而且我需要知道是否有任意数量的员工对每个技能都有正面的技能评分 。
So let's say I want to look at this info for employees 120 , 348 , 361 and 370 . 所以我们可以说我想看看这个信息对员工120,348,361和370。
Query 1 for skill WLN
is: 技能
WLN
查询1为:
SELECT `Emp_ID`, `Rating` > 0 AS `WLN` FROM `Emp_Skill` WHERE `Skill_ID` = 'WLN' AND `Emp_ID` IN (120,348,361,370)
which returns: 返回:
Emp_ID WLN
------------
120 1
348 1
361 1
370 1
Query 2 for skill LOC
is: 技能
LOC
查询2为:
SELECT `Emp_ID`, `Rating` > 0 AS `LOC` FROM `Emp_Skill` WHERE `Skill_ID` = 'LOC' AND `Emp_ID` IN (120,348,361,370)
which returns: 返回:
Emp_ID LOC
------------
120 1
348 1
361 1
370 1
Query 3 for skill BRV
is: 技能
BRV
查询3为:
SELECT `Emp_ID`, `Rating` > 0 AS `BRV` FROM `Emp_Skill` WHERE `Skill_ID` = 'BRV' AND `Emp_ID` IN (120,348,361,370)
which returns: 返回:
Emp_ID BRV
------------
120 1
348 1
and Query 4 for skill KSD
is: 技能
KSD
查询4为:
SELECT `Emp_ID`, AVG(`Rating`) > 0 AS `KSD` FROM `Emp_Skill` WHERE `Skill_ID` IN ('KWH','SIC','DOL') AND `Emp_ID` IN (120,348,361,370) GROUP BY `Emp_ID`
which returns: 返回:
Emp_ID KSD
------------
120 1
348 1
361 1
370 1
Question is: How do I efficiently combine these queries into one result table and have them all in one go , ie: 问题是: 如何有效地将这些查询组合到一个结果表中,并将它们全部合并在一起 ,即:
Emp_ID WLN LOC BRV KSD
------------------------------
120 1 1 1 1
348 1 1 1 1
361 1 1 NULL? 1
370 1 1 NULL? 1
possibly from a combined SELECT
statement? 可能来自组合的
SELECT
语句? (the NULL
value could be anything that evaluates to FALSE
in the returned result set) (
NULL
值可以是返回结果集中评估为FALSE
任何值)
OR : performance-wise, will it be better if I just query each skill rating one by one (using the 4 queries above)? 或者 :从性能角度来看,如果我一个接一个地查询每个技能等级(使用上面的四个查询)会更好吗?
Sorry if this is elementary for some peeps out there, but I've pulled a lot of hair out and I still haven't killed this. 抱歉,如果这对于那里的一些偷窥而言是基本的,但是我已经拉了很多头发,但我仍然没有杀死它。 lol.
大声笑。 Thanks in advance.
提前致谢。
This is done with a pivot query, which amounts to a bunch of CASE
statements. 这是通过数据透视查询完成的,该查询相当于一堆
CASE
语句。 I think this should get you close to what you need: 我认为这应该使您接近所需的内容:
SELECT
Emp_ID,
MAX(CASE WHEN Skill_ID = 'WLN' THEN (Rating > 0) END) AS `WLN`,
MAX(CASE WHEN Skill_ID = 'LOC' THEN (Rating > 0) END) AS `LOC`,
MAX(CASE WHEN Skill_ID = 'BRV' THEN (Rating > 0) END) AS `BRV`,
AVG(CASE WHEN Skill_ID IN ('KWH','SIC','DOL') THEN (Rating > 0) END) AS `KSD`
FROM Emp_Skill
GROUP BY Emp_ID
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