[英]How to invokePrivate on a function with implicit parameters
How do I invoke XYZ.doSomething method for these classes: 如何为这些类调用XYZ.doSomething方法:
XYZ.scala XYZ.scala
object XYZ {
private def doSomething(i : Int)(implicit s: String): String {
s + i.toString
}
}
XYZTest.scala XYZTest.scala
class XYZTest extends FunSpec with PrivateMethodTester {
describe("SomeTest") {
it("Can't find a private method named: doSomething :( ") {
implicit lazy val someStr: String = "sahil"
val doSomething = PrivateMethod[String]('doSomething)
val myStr = XYZ invokePrivate doSomething(1)
assert(myStr == "sahil1")
}
}
describe("SomeTest") {
it("This doesn't even compile :( ") {
val doSomething = PrivateMethod[String]('doSomething)
val myStr = XYZ invokePrivate doSomething(1)("sahil")
assert(myStr == "sahil1")
}
}
}
Correct answer is: 正确答案是:
object XYZ {
private def doSomething(i : Int)(implicit s: String): String = {
s + i.toString
}
}
class XYZTest extends FunSpec with PrivateMethodTester {
describe("SomeTest") {
it("Can't find a private method named: doSomething :( ") {
implicit lazy val someStr: String = "sahil"
val doSomething = PrivateMethod[String]('doSomething)
val myStr = XYZ invokePrivate doSomething(1, someStr)
assert(myStr == "sahil1")
}
}
}
Brief view on invokePrivate
method shows that it does not support implicits
, but looks like it treats currying
argument list as general sequence of arguments 关于invokePrivate
方法的简要视图表明,它不支持implicits
,但看起来像将currying
参数列表视为参数的一般顺序
def invokePrivate[T](invocation : PrivateMethodTester.this.Invocation[T])
where args
is the sequence: 其中args
是序列:
final class Invocation[T](val methodName : scala.Symbol, val args : scala.Any*)
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