如何在具有隱式參數的函數上調用Private

Question

如何為這些類調用XYZ.doSomething方法：

XYZ.scala

object XYZ {

  private def doSomething(i : Int)(implicit s: String): String {
    s + i.toString
  }
}

XYZTest.scala

class XYZTest extends FunSpec with PrivateMethodTester {
  describe("SomeTest") {
    it("Can't find a private method named: doSomething :( ") {
      implicit lazy val someStr: String = "sahil"
      val doSomething = PrivateMethod[String]('doSomething)
      val myStr = XYZ invokePrivate doSomething(1)
      assert(myStr == "sahil1")
    }
  }
  describe("SomeTest") {
    it("This doesn't even compile :( ") {
      val doSomething = PrivateMethod[String]('doSomething)
      val myStr = XYZ invokePrivate doSomething(1)("sahil")
      assert(myStr == "sahil1")
    }
  }
}

Answer 1

正確答案是：

object XYZ {

  private def doSomething(i : Int)(implicit s: String): String = {
    s + i.toString
  }
}

class XYZTest extends FunSpec with PrivateMethodTester {
  describe("SomeTest") {
    it("Can't find a private method named: doSomething :( ") {
      implicit lazy val someStr: String = "sahil"
      val doSomething = PrivateMethod[String]('doSomething)
      val myStr = XYZ invokePrivate doSomething(1, someStr)
      assert(myStr == "sahil1")
    }
  }
}

關於invokePrivate方法的簡要視圖表明，它不支持implicits ，但看起來像將currying參數列表視為參數的一般順序

def invokePrivate[T](invocation : PrivateMethodTester.this.Invocation[T])

其中args是序列：

final class Invocation[T](val methodName : scala.Symbol, val args : scala.Any*)