如何用空格分割字符串并在结果中包含空格作为元素？多个空格分割

Question

The code I used to split the string with any number of white space is

String out="SELECT * FROM EMP WHERE EMPID=10";
String array[] = out.split("\\s+");

I want to include the white spaces in the "out" string into the array[] object while splitting with white spaces. The output I want is:

array[]={"SELECT","[WHITE SPACE]","*","[WHITE SPACE]","FROM","[WHITE SPACE]","EMP","[WHITE SPACE]","WHERE","[WHITE SPACE]","EMPID=10"}

But the output what I am getting is:

 array[]={"SELECT","*","FROM","EMP","WHERE","EMPID=10"}

Any help will be appreciated

Answer 1

Since split accepts a regex, you can use lookarounds :

out.split("(?<=\\s)|(?=\\s)");

This will output:

[SELECT,  , *,  , FROM,  , EMP,  , WHERE,  , EMPID=10]

Note that the delimiter (space in your case) is included in the result.

Answer 2

Try to split it like this:

  String array[] = out.split("(?=\\s)",-1);

The code is:

 public static void main(String[] args) {
    String out="SELECT * FROM EMP WHERE EMPID=10";
    String array[] = out.split("(?=\\s)",-1);

    for (String string : array) {       
    System.out.print(string);
    }
  }

Output:

SELECT * FROM EMP WHERE EMPID=10

Answer 3

Try this one,

String out="SELECT * FROM EMP WHERE EMPID=10";
    out = out.replaceAll("\\s+", ",[WHITE SPACE],");

    String [] array = out.split(",");

    ArrayList<String> list = new ArrayList<String>();

    for(String str : array){
        list.add(str);
    }
    System.out.println(list);

output :