遍历python字典吗？

Question

I have a dictionary where the keys are integers and the values are strings. The dictionary has been sorted using key values. I need to copy the corresponding string values (keeping the sorted order) to a list. I cannot figure out how to iterate over the dictionary.

I know the number of key-value pairs in the dictionary (let it be 'n').

    Some_ordered_dict
    resultant_list=[]
    for i in range(n):
        resultant_list.append(Some_ordered_dict[increment-key?]

The dictionary was sorted using OrderedDict from some dictionary 'dic' as follows;

    od=collections.OrderedDict(sorted(dic.items()))

The essential point is that I have to display the strings values of the dictionary in the same order as they appear in the sorted dictionary.

Answer 1

resultant_list = [d[k] for k in sorted(d)]

Answer 2

The standard Python dictionary does not guarantee that items in a dictionary will be kept in any order. Next thing is that you have to iterate using a "for in" statement like such:

Some_ordered_dict
    resultant_list=[]
    for i in Some_ordered_dict:
        resultant_list.append(Some_ordered_dict[i])

You should take a look at the ordered dict collection to ensure that the items on your dict are kept in the order that you expect.

Answer 3

Using the standard unordered dictionary in python you could use something like this:

resultant_list = []
for i in sorted(dict.keys()):
    resultant_list.append(dict[i])

Answer 4

As mentioned in other posts, dictionaries do not guarantee order. One way to get a sorted list would be to created a list of tuples out of your dict's (key, value) pairs, then sort this list based n the first element(the key), as follows:

my_dict = {2: 'two', 3: 'three', 1: 'one'}
my_tuple_list = list(zip(my_dict.keys(), my_dict.values()))
my_sorted_list = sorted(my_tuple_list, key = lambda item: item[0])
resultant_list = [x[1] for x in my_sorted_list]