在Python中解析XML Pastebin响应

Question

I'm trying to search for something on Pastebin, via their API. I'm searching using the pastebin library for python.

The problem is that I receive an XML response, that has repeating keys.

This is the response

<paste>
<paste_key>fadsda</paste_key>
<paste_date>1409074286</paste_date>
<paste_title>badPaste</paste_title>
<paste_size>2040</paste_size>
<paste_expire_date>0</paste_expire_date>
<paste_private>0</paste_private>
<paste_format_long>Bash</paste_format_long>
<paste_format_short>bash</paste_format_short>
<paste_url>http://pastebin.com/url2</paste_url>
<paste_hits>211</paste_hits>
</paste>
<paste>
<paste_key>fsfgdsgg</paste_key>
<paste_date>1398409838</paste_date>
<paste_title>goodPaste</paste_title>
<paste_size>2407</paste_size>
<paste_expire_date>0</paste_expire_date>
<paste_private>2</paste_private>
<paste_format_long>Bash</paste_format_long>
<paste_format_short>bash</paste_format_short>
<paste_url>http://pastebin.com/otherURL</paste_url>
<paste_hits>54</paste_hits>
</paste>

So I am trying to parse it to return paste_key when paste_title == goodPaste , but the attrib is always empty

def parseXML(response):
    #I'm adding a root tag
    xml = ElementTree.fromstring('<list>' + response + '</list>')
    for child in root:
            for elem in child:
                print elem.tag, elem.attrib

returns

    paste_key {}
    paste_date {}
    paste_title {}
    paste_size {}
    paste_expire_date {}
    paste_private {}
    paste_format_long {}
    paste_format_short {}
    paste_url {}
    paste_hits {}
    paste_key {}
    paste_date {}
    paste_title {}
    paste_size {}
    paste_expire_date {}
    paste_private {}
    paste_format_long {}
    paste_format_short {}
    paste_url {}
    paste_hits {}

EDIT : So I was supposed to use elem.text, so that's working now, but the main question still exists: How can I return the element where paste_key when paste_title == goodPaste

EDIT 2 Winning ticket:

result = xml.findall(".//paste[paste_title='goodPaste']/paste_key")
print result[0].text

Answer 1

You can use XPath for that:

result = xml.findall(".//paste[paste_title='goodPaste']/paste_key")
print result.text

This should print fsfgdsgg in your case