[英]Insert Row in Python Pandas DataFrame
(I´m new to python, sorry for any mistakes I make, I hope you can understand me) (我是python的新手,对我犯的任何错误深表歉意,希望你能理解我)
I have searched for a method to insert a Row into a Pandas DataFrame in Python, and I have found this: 我搜索了一种在Python中将行插入到Pandas DataFrame中的方法,并且发现了这一点:
add one row in a pandas.DataFrame 在pandas.DataFrame中添加一行
I have use the code provided in the accepted answer of that topic by fred, but the code overwrites my row: My code (Inserts a row with values "-1" for each column in certains conditions): 我已经使用了fred在该主题的可接受答案中提供的代码,但是该代码覆盖了我的行:我的代码(在某些情况下,每列插入值为“ -1”的行):
df.loc[i+1] = [-1 for n in range(len(df.columns))]
How can I make the code insert a row WITHOUT overriding it? 如何使代码插入一行而不覆盖它? For example, if I have a 50 row DataFrame, insert a row in position 25 (Just as an example), and make the DataFrame have 51 rows (Being the 25 a extra NEW row). 例如,如果我有一个50行的DataFrame,则在位置25插入一行(仅作为示例),并使DataFrame具有51行(将25行作为一个额外的NEW行)。
I hope you can understand my question. 希望你能理解我的问题。 (Sorry for any english mistakes) (对于任何英语错误深表歉意)
Thank you. 谢谢。
UPDATE: 更新:
Someone suggested this: 有人建议这样做:
Is it possible to insert a row at an arbitrary position in a dataframe using pandas? 是否可以使用熊猫在数据框中的任意位置插入一行?
Tried, did not work. 试过了,没有用。 In fact, it does nothing, does not add any row. 实际上,它什么也不做,不添加任何行。
line = pd.DataFrame({[-1 for n in range(len(df.columns))]}, index=[i+1])
df = pd.concat([ df.ix[:i], line, df.ix[i+1:]]).reset_index(drop=True)
Any other ideas? 还有其他想法吗?
With a small DataFrame
, if you want to insert a line, at position 1
: 对于较小的DataFrame
,如果要在位置1
插入一行:
df = pd.DataFrame({'a':[0,1],'b':[2,3]})
df1 = pd.DataFrame([4,5]).T
pd.concat([df[:1], df1.rename(columns=dict(zip(df1.columns,df.columns))), df[1:]])
#Out[46]:
# a b
#0 0 2
#0 4 5
#1 1 3
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