通过collect封闭改进Groovy列表迭代

Question

I have a functioning Groovy 2.4.3 method that I think I can make even groovier by using the collect() closure, but not exactly sure how:

List<Buzz> deriveBuzzesFromFizz(Fizz fizz) {
    List<Buzz> buzzes = []
    fizz.foobars?.each {
        if(it.label.equals('whistlefeather')) {
            buzzes << it
        }
    }

    buzzes
}

Perhaps something like:

List<Buzz> buzz = fizz.foobars?.collect {
    it.label.equals('whistlefeather')
}

...or thereabouts?!

Answer 1

You're thinking of a findAll

fizz.foobars?.findAll {
    it.label == 'whistlefeather'
}