如何从bash脚本同时启动多个Ruby脚本

Question

How can I launch several different ruby scripts in order from a bash script?

I've managed to achieve it on my Windows machine with a batch file but I'm struggling to figure out how to do it with bash.

Here's the contents of my batch file for reference:

start "1" cmd /k ruby replicaServer.rb
start "2" cmd /k ruby FileServer.rb
start "3" cmd /k ruby fileServer2.rb
start "4" cmd /k ruby directoryServer.rb
start "5" cmd /k ruby LockServer.rb
start "6" cmd /k ruby ClientProxy.rb
start "7" cmd /k ruby client.rb

Answer 1

How about

/usr/local/bin/ruby replicaServer.rb &
/usr/local/bin/ruby FileServer.rb &
/usr/local/bin/ruby fileServer2.rb &
/usr/local/bin/ruby directoryServer.rb &
/usr/local/bin/ruby LockServer.rb &
/usr/local/bin/ruby ClientProxy.rb &
/usr/local/bin/ruby client.rb &

Adjust the path to wherever you actually keep the ruby executable, lose the ampersands if you want things to run sequentially rather than in parallel.