[英]Python regular expression to extract the parenthesis
I have the following unwieldy code to extract out 'ABC' and '(XYZ)' from a string 'ABC(XYZ)' 我有以下繁琐的代码从字符串“ ABC(XYZ)”中提取“ ABC”和“(XYZ)”
import re
test_str = 'ABC(XYZ)'
partone = re.sub(r'\([^)]*\)', '', test_str)
parttwo_temp = re.match('.*\((.+)\)', test_str)
parttwo = '(' + parttwo_temp.group(1) + ')'
I was wondering if someone can think of a better regular expression to split up the string. 我想知道是否有人可以想到更好的正则表达式来拆分字符串。 Thanks.
谢谢。
You may use re.findall
您可以使用
re.findall
>>> import re
>>> test_str = 'ABC(XYZ)'
>>> re.findall(r'\([^()]*\)|[^()]+', test_str)
['ABC', '(XYZ)']
>>> [i for i in re.findall(r'(.*)(\([^()]*\))', test_str)[0]]
['ABC', '(XYZ)']
[i for i in re.split(r'(.*?)(\(.*?\))', test_str) if i]
For this kind of input data, we can replace the (
with space+ (
and split by space: 对于这种输入数据,我们可以将
(
替换为space + (
并按空格分隔:
>>> s = 'ABC(XYZ)'
>>> s.replace("(", " (").split()
['ABC', '(XYZ)']
This way we are artificially creating a delimiter before every opening parenthesis. 这样,我们在每个括号前都人为地创建了一个定界符 。
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