用于删除带括号的文本的正则表达式

Question

Take this text for example泣（な）き出（だ）した, I want to remove the furigana programmatically (ie.泣き出した). I tried

re.sub(r"\（[^()]*\）", "", '泣（な）き出（だ）した')

but it returns泣したinstead. What is the better regular expression?

Answer 1

The parentheses in your character class are half-width (半角) instead of full-width (全角) parentheses.

Replacing them will fix your problem:

import re

re.sub(r"\（[^（）]*\）", "", '泣（な）き出（だ）した')

# '泣き出した'

Answer 2

You should try re.sub(r"\（.*?\）", "", '泣（な）き出（だ）した') , which uses the non-greedy quantifier *? .