[英]display a subset of regions using a shapefile in R
I have a shapefile of the UK: https://geoportal.statistics.gov.uk/Docs/Boundaries/Local_authority_district_(GB)_2014_Boundaries_(Generalised_Clipped).zip 我有一个英国的shapefile: https ://geoportal.statistics.gov.uk/Docs/Boundaries/Local_authority_district_(GB)_2014_Boundaries_(Generalised_Clipped).zip
I've read the shapefile into a variable, UK 我已经将shapefile读入变量,英国
>UK <- readOGR(dsn = "....."
>England <- UK
I'd like to only display English Local Authority regions. 我只想显示英语地方当局地区。 They are specified in the LAD_DEC_2014_GB_BGC.dbf where LAD14CD starts with "E" 它们在LAD_DEC_2014_GB_BGC.dbf中指定,其中LAD14CD以“ E”开头
>UK@data
LAD14CD LAD14NM LAD14NMW
0 E06000001 Hartlepool <NA>
1 E06000002 Middlesbrough <NA>
2 E06000003 Redcar and Cleveland <NA>
371 W06000015 Cardiff Caerdydd
>#filter UK@data and replace England@data with only English regions
>England@data <- UK@data$LAD14CD[c(grep("^E", UK$LAD14CD))]
>plot(England)
But the grep command appears to change the shapefile into a factor, meaning the plot looks like this: 但是grep命令似乎将shapefile更改为一个因子,这意味着该图看起来像这样:
With this command: 使用此命令:
England <- UK@data$LAD14CD[c(grep("^E", UK$LAD14CD))]
...you are subsetting just one column from the data slot, not the whole shapefile and assigning that to England
. ...您只在数据槽中分配一列,而不是整个shapefile并将其分配给England
。
This ought to do the job: 这应该做的工作:
England <- UK[grep("^E", UK@data$LAD14CD),]
Note, you need the trailing comma in there! 请注意,您需要在其中加上逗号! Also you don't need to wrap the grep statement in c()
, but that doesn't hurt it's just unnecessary. 另外,您不需要将grep语句包装在c()
,但这并没有什么害处,这只是不必要的。
I ended up using dplyr
and grepl
instead to make things simpler: 我最终使用dplyr
和grepl
简化了事情:
library('rgdal')
library('dplyr')
UK <- readOGR(dsn="LAD_DEC_2014_GB_BGC.shp", layer="LAD_DEC_2014_GB_BGC") %>%
subset(grepl("^E", LAD14CD))
plot(UK)
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