如何在C＃中获取包含另一个xml节点的节点

Question

I have few xml documents. and each document has different nodes. Only thing common is it has _Header and _Table nodes. what i want is to get the parent nodes which contain _Header and _Table nodes.

I want the program to output the following nodes:

_StatementofNetAssets_T1
_StatementofNetAssets_T2
_StatementofNetAssets_T3

How can I do this?

Answer 1

XmlDocument xmlDoc=new XmlDocument(); 
string xmlname=Server.MapPath("*.xml").ToString();
xmlDoc.Load(xmlname); 
XmlNodeList    nodeList=xmlDoc.SelectSingleNode("form/Documents").ChildNodes;//get all child nodes
foreach(XmlNode xn in nodeList) 
{ 
  XmlElement xe2=(XmlElement)xn;

  if(xe2.InnerText=="_Header"||xe2.InnerText=="_Table nodes")
  {
    XmlNode xn3=xn.ParentNode; 
    XmlElement xe=(XmlElement)xn3; 
    Console.WriteLine(xe.InnerText);
   }
} 

Answer 2

You could use XDocument class and XPath to quickly parse your documents

var elements = XDocument.Load(path).XPathSelectElements("//_Header").Select(q => q.Parent);

You will be needing these namespaces

using System.Linq;
using System.Xml.XPath;