如何从C ++中的txt文件输出。 该文件有一两行

Question

The rows are as in the example:

583-4-153-15601-4  '\t' Time Warp Trio  '\t'  Scieszka Jon    '\t' 50  '\t'  50
583-0-133-15601-2  '\t'  Djemte e rruges pal    '\t'    Ardit Zotaj '\t' 50  '\t'  50

So Every string is separated by a tab. Basically it contains the information for a book.

ISBN-TITLE-AUTHOR-PRICE-NO. OF COPIES.<
//583-4-153-15601-4  '\t' Time Warp Trio  '\t'  Scieszka Jon    '\t' 50  '\t'  50
//583-0-133-15601-2  '\t'  Djemte e rruges pal    '\t'  Ardit Zotaj '\t' 50  '\t'  50

I have done this work so far but it doesn't give the right output me in the cmd.

#include <iostream>
#include <string>
#include <fstream>
#include <sstream>
using namespace std;

int main()
{ 
    ifstream fin;
    fin.open("bookdata.txt");
    string line;
    string isbn, title, author;
    int var1 = 0;
    int var2 = 2;

    while (!fin.eof())
    {
        getline(fin, isbn, '\t');
        getline(fin, title, '\t');
        getline(fin, author, '\t');
        fin >> var1;
        fin >> var2;
    }

    cout << isbn << title << author << endl;
    fin.close();
    cout << var1 << var2 << endl;
}

Answer 1

Try something like this (not tested):

while (getline(fin, isbn, '\t') && getline(fin, title, '\t') &&
       getline(fin, author, '\t') && fin >> var1 && fin >> var2 &&
       fin.ignore(std::numeric_limits<std::streamsize>::max(), '\n'))
{
    cout << isbn << title << author << " " << var1 << " " << var2 << endl;
}

I used fin.ignore , so that we don't get \\n , which is still in the stream after fin >> var2 , as the first character of the next isbn . It could be also fin.ignore(1, '\\n') ...

You also have to print these variables in the loop, otherwise you'll just print the information of the last row in the file.

I also noticed, that you have string line; lying around. Another approach, now utilizing this object can be found here .