[英]How do I call an GUI function from Main class in Python?
I need ProgressBar
widget in my_app ,When I click on the pushButton
, I can not call def call_progressBar2(self,value1)
in def download (self)
. 我需要my_app中的
ProgressBar
小部件,单击pushButton
,无法在def download (self)
调用def call_progressBar2(self,value1)
def download (self)
。 Can anyone help me? 谁能帮我?
main.py main.py
from g import Ui_MainWindow
from PyQt4 import QtCore, QtGui
import sys
import time
from b import classb
class MainWindow(QtGui.QMainWindow):
def __init__(self, parent=None):
QtGui.QWidget.__init__(self, parent)
self.ui = Ui_MainWindow()
self.ui.setupUi(self)
instance_b=classb()
tvt= self.call_progressBar2(self)
QtCore.QObject.connect(self.ui.pushButton1, QtCore.SIGNAL("clicked()"), \
lambda: instance_b.download(tvt))## I need help here.
def call_progressBar2(self,value1):
while True:
time.sleep(0.05)
value = self.ui.progressBar.value() + 1
self.ui.progressBar.setValue(value)
QtGui.qApp.processEvents()
if (not self.ui._active or
value >= self.progressBar.maximum()):
if value==value1:
break
self.ui._active = False
if __name__ == "__main__":
app = QtGui.QApplication(sys.argv)
myapp = MainWindow()
myapp.show()
sys.exit(app.exec_())
b.py b.py
import time
from PyQt4 import QtCore, QtGui
class classb (object):
def __init__(self, parent=None):
self.parent=parent
#I need call def call_progressBar2() here.
def download(self):
from main import MainWindow
instance_m= MainWindow
print 'a'
instance_m.call_progressBar2(20)
print 'b'
instance_m.call_progressBar2(40)
print 'c'
instance_m.call_progressBar2(60)
print 'd'
instance_m.call_progressBar2(100)
Why don't you just pass the current MainWindow
instance to your download
function when you connect the signal ? 当连接信号时,为什么不将当前的
MainWindow
实例传递给download
函数呢? Or just pass it to classb
initialiser when you instanciate it just before you connect the signal ? 还是在连接信号之前实例化它时将其传递给
classb
初始化程序? Or specify download
so it takes a callback, and pass the MainWindow
current instance's call_progressBar2
method as callback when you connect the signal ? 还是指定
download
以便进行回调,并在连接信号时将MainWindow
当前实例的call_progressBar2
方法作为回调传递?
Instead of creating instance of MainWindow
in classb.download
method, just pass it as parameter when you connect the signal, this way: 不用在
classb.download
方法中创建MainWindow
实例,而是在连接信号时将其作为参数传递,方法是:
#tvt= self.call_progressBar2(self) #No need for tvt
QtCore.QObject.connect(self.ui.pushButton1, QtCore.SIGNAL("clicked()"), \
lambda: instance_b.download(self)) #self here is the MainWindow Instance
Then in classb.download
method: 然后在
classb.download
方法中:
def download(self, main_window):
print 'a'
main_window.call_progressBar2(20)
print 'b'
main_window.call_progressBar2(40)
print 'c'
main_window.call_progressBar2(60)
print 'd'
main_window.call_progressBar2(100)
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.