分配等效于std :: atomic的加载/存储<bool>

Question

I see that this is potentially answered in question Must I call atomic load/store explicitly? .

So for sake of clarity I will restate my question succinctly in the hopes that future readers find this clear.

Is

std::atomic<bool> b(false);
bool x = b;

Same as

std::atomic<bool> b(false);
bool x = b.load();

And

std::atomic<bool> b(false);
b = true;

Same as

std::atomic<bool> b(false);
b.store(true);

If this is indeed the case then:

1. why have 2 options? what is the apparent benefit?
2. Is it good practice when dealing with atomics to prefer the more verbose load()/store() over the potentially confusing assignment(=) which could mean either depending on whether LHS or RHS is the atomic.

NOTE I am already aware of the fact that both variables cannot be std::atomic ie LHS and RHS as it is not possible to read and write atomically in one instruction.

Answer 1

Yes, they are the same. I think the reason the overloaded operators are provided is for convenience. Not to mention making it easier to convert existing code to use atomics.

Personally, I prefer to be explicit with load and store always. I think it's better practice and forces you to remember that you're dealing with an atomic.

Also, those functions allow you to specify other memory orders, which is not possible with the overloaded operator versions.