发送一部分request.path到url_for Python / HTML

Question

my url is http://example.com/en/cat/ap+da+w_pl Now I have a-tag like this:

<a href="{{ url_for('category',
                    feature=request.path+"+"+att.get('u_sg'))}}">
                    {{ att.get('name') }}
                </a>

request.path is giving me ' /en/cat/ap+da+wh_pl ' BUT, I need only /ap+da+w_pl How to do it?

I need to pass only 'ap+da+w_pl' from out of request.path from HTML only, as I have to use it in pre-coded View of Flask and my view is like THIS:

@app.route('<lan_c>/cat/<string:feature>')
def category(feature, page):

• Consider current url is ' http://example.com/en/cat/ap+da+w_pl ' if user click on a-tag then I want to append value returned from 'att.get('u_sg')'.
• The problem I am facing right now is my a-tag is considering ' http://example.com/ en/cat/en/cat /ap+da+w_pl+w_pl2', so I wanted to send only 'ap+da+w_pl' + 'att.get('u_sg')'. So that a-tag will point to ' http://example.com/en/cat/ap+da+w_pl+w_pl2 '

Answer 1

You could split the result by / and get the last key:

>>> r = 'http://example.com/en/cat/ap+da+w_pl'.split('/')
>>> r[-1]
'ap+da+w_pl'

This would work for /en/cat/ap+da+wh_pl the same way:

>>> r = '/en/cat/ap+da+w_pl'.split('/')
>>> r[-1]
'ap+da+w_pl'

Prepend the / if needed:

>>> '/'+(r[-1])
'/ap+da+w_pl'