Django 在不使用“request.path”的情况下获取 url 路径

Question

I am creating a 404.html page in django which will be called when i raise "Http404"

I dont know if 404.html will be passed a "RequestContext" object but can I generate the requested url path without using request variable

I tried "request.path" and "request.get_full_path" but they dont work for me.

Any help would be appreciated.

Answer 1

The 404 template will be rendered with a request context (unlike the 500 server error template).

Make sure that the django.core.context_processors.request context processor is in your TEMPLATE_CONTEXT_PROCESSORS setting. Note that it is not included by default.

Once you've done that, the request methods that you mention like get_full_path should work.