三元运算符是什么意思

Question

I have this piece of code I'm going to translate into mips but I don't know what it means: A = B & C[0]

When I google ternary operator I can't find any mention of the & , just e1 ? e2 : e e1 ? e2 : e

What does it mean?

Answer 1

There's no ternary operator here. The expression is equivalent to A = (B & C[0]) , that is A is assigned with the result of bitwise AND applied to B and C[0] .

Answer 2

 bitwise AND

Take a look at this: https://docs.oracle.com/javase/tutorial/java/nutsandbolts/op3.html

And look here for an example http://www.tutorialspoint.com/java/java_bitwise_operators_examples.htm

Answer 3

The & here is the binary (2 inputs) operator "bitwise and". In this case you have:

A = B & C[0];

So A will receive the results of the bit-by-bit and-ing of B and C[0] . Lets imagine that A, B and C[0] are two 32 bit integers, that have values I randomly assigned them, and lets view this operation in binary:

B    = 0000 0001 0010 0100 1000 1001 1011 1111
C[0] = 1001 1110 1101 1101 1010 1010 1010 0101
A    = 0000 0000 0000 0100 1000 1000 1010 0101 (the and of the two values above)

that is, A has a 1 bit only where both B and C[0] have 1 bits.

In decimal this is 19171775 & 2665327269 = 297125 .

BTW, a ternary operator has 3 inputs, most common being ?: , as in R = C ? B : A R = C ? B : A .