[英]How dynamically create a Character in Swift 2.1
I have a file with this string: 我有一个包含此字符串的文件:
N\u00e3o informado
Than I read it and put in a variable 比我阅读并放入一个变量
let myString = NSString(contentsOfFile: filename, encoding: NSUTF8StringEncoding)
print(mystring) // get "N\u00e3o informado"
Then I want to convert the \ã
to your unicode value = ã
. 然后,我要将\ã
转换为您的unicode值= ã
。 I read in Swift Book this line: 我在Swift Book中读到了这一行:
let text = "Voulez-vous un caf\u{65}\u{301}?"
And I tried create the same thing dynamicaly, but it didn't worked: 我尝试动态地创建相同的东西,但是没有用:
let substring = "00e3"
dinamic = "N\u{\(substring)}o informado" //This produce the equivalent
print(dinamic) // get "N\u{00e3}o informado" but I want "Não informado"
In the same way, this not work 同样,这不起作用
let code = "00e3"
let caracter = Character("\u{\(code)}") //compile error
let caracter = Character("\\u{\(code)}") //runtime error
let number = 00e3
let caracter = Character(number) //compile error
let caracter = Character("\u{00e3}") //This work, but isn't dinamic
How can I do this? 我怎样才能做到这一点?
First convert your String
to an Int
telling Int
that it is in base 16, then create a UnicodeScalar
from the Int
, and finally create the Character
from the UnicodeScalar
: 首先将您的String
转换为一个Int
告诉Int
它位于基数16,然后从Int
创建一个UnicodeScalar
,最后从UnicodeScalar
创建一个Character
:
let code = "00e3"
let character = Character(UnicodeScalar(Int(code, radix: 16)!))
If you'd prefer to have a String
instead of a Character
, then: 如果您希望使用String
而不是Character
,那么:
let string = String(UnicodeScalar(Int(code, radix: 16)!))
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