Bash脚本将十进制IP转换为二进制

Question

I need to write a script to enter 2 IP addresses and then change them to binary. I tried this script but it works just with numbers. I can't write the IP thus: 192.168.1.1 , but when I write it as 100 it's working fine.

#!/bin/bash  
echo "Ebter the first ip"
read ip1
echo "Enter the second ip"
read ip2

a=`echo "obase=2;$ip1" | bc`
b=`echo "obase=2;$ip2" | bc`
echo $a
echo $b  

What is wrong in my script?

Answer 1

what you can do:

#!/bin/bash

function convip()
{
    CONV=({0..1}{0..1}{0..1}{0..1}{0..1}{0..1}{0..1}{0..1})

    ip=""
    for byte in `echo ${1} | tr "." " "`; do
        ip="${ip}.${CONV[${byte}]}"
    done
    echo ${ip:1}
}

echo "Enter the first ip"
read ip1
echo "Enter the second ip"
read ip2

a=`convip "${ip1}"`
b=`convip "${ip2}"`

echo "${a}"
echo "${b}"

Result:

Enter the first ip
1.1.1.1
Enter the second ip
2.2.2.2
00000001.00000001.00000001.00000001
00000010.00000010.00000010.00000010

EDIT: updated to keep dots