python通过名称而不是PID杀死script.py

Question

one script starts automatically when my raspberry is booted up, within this script there is motion sensor, if detected, it starts a subproces camera.py (recording a video, then converts the video and emails)

within the main script that starts u on booting up, there is another if statement, if button pressed then stop the camera.py and everything in it and do something else.

I am unable to kill process by PID because it keeps changing. The only other option is to kill camera.py by its name, but it doesn't work.

main script:

p1 = subprocess.Popen("sudo python /home/pi/camera.py", shell=True)

this is my camera.py script:

import os
os.system("raspivid -n -o /home/pi/viseo.h264 -t 10000")
os.system(.... python script0.py
os.system(.... python script1.py

i can do:

os.system("sudo killall raspivid")

if i try

os.system("sudo killall camera.py")

it gives me a message: No process found

this only stops the recording but i also want to kill every other script within camera.py

Can anyone help please? thanks

Answer 1

使用pkill ：

$ sudo pkill -f camera.py 

Answer 2

如果您将camera.py设为可执行文件，请将其放在$ PATH上，并使脚本#!/usr/bin/python 1行生效，然后在不带python命令的情况下执行camera.py，即"sudo killall camera.py"命令应该可以正常工作。

Answer 3

instead of using:

import os
os.system("raspivid -n -o /home/pi/viseo.h264 -t 10000")
os.system(.... python script0.py)
os.system(.... python script1.py)

you should use the same Popen structure as how you spawn this process. This gives you access to the Popen object of the calls.

import os 
pvid = subprocess.Popen("raspivid -n -o /home/pi/viseo.h264 -t 10000")
p1 = subprocess.Popen(.... python script0.py)
p2 = subprocess.Popen(.... python script1.py)

Then you can get the pid of all the different scripts and kill them through that.

This should actually be done through an shutdown sequence. You should never Force close applications if you can let it close itself.