如何引用匿名函数Javascript的父参数

Question

I'm trying to figure out how I can reference an argument on a wrapper function stored in a variable that calls an anonymous function. Such as in the example below. The problem I run into is I'm used to accessing parameters via the arguments variable, but that sees only the parameter myFunc. I know it's supposed to be possible, but I can't figure out how.

var myFunc = function(arg1, arg2){//do stuff}
var myFuncWrapped = wrapper(myFunc);

myFuncWrapped('arg value1', 'arg value2');

function wrapper(func){
  //how can I reference 'arg value1' from here since arguments == myFunc?
}

Answer 1

As the comment suggested, wrapper should be returning a function so you can capture the arguments via closure when myFuncWrapped gets called.

var myFunc = function(arg1, arg2) {
    console.log(arg1); // (For testing only) Should be"arg value1"
};

var myFuncWrapped = wrapper(myFunc);

myFuncWrapped('arg value1', 'arg value2');

function wrapper(func) {
    /* The anonymous function below is actually the one
     * being called when you invoke "myFuncWrapped" so it has the arguments you need.
     */
    return function() {
        console.log(arguments[0]); // (For testing only) Should be"arg value1"
        func.apply(this, arguments);
    }
}