[英]How to position one element relative another using CSS/jQuery
I'm tring to position the title
in the following code center to the circle
. 我想将
title
放置在circle
的以下代码中心。
<style>
*, *:after, *:before {
margin: 0;
padding: 0;
box-sizing: border-box;
font-family: "Open Sans";
}
/* Form Progress */
.progress {
width: 1500px;
margin: 20px auto;
text-align: center;
}
.progress .circle,
.progress .bar {
display: inline-block;
background: #fff;
width: 40px; height: 40px;
border-radius: 40px;
border: 1px solid #d5d5da;
}
.progress .bar {
position: relative;
width: 100px;
height: 6px;
top: -33px;
margin-left: -5px;
margin-right: -5px;
border-left: none;
border-right: none;
border-radius: 0;
}
.progress .circle .label {
display: inline-block;
width: 32px;
height: 32px;
line-height: 32px;
border-radius: 32px;
margin-top: 3px;
color: #b5b5ba;
font-size: 17px;
}
.progress .circle .title {
color: #b5b5ba;
font-size: 13px;
line-height: 30px;
margin-left: -5px;
}
/* Done / Active */
.progress .bar.done,
.progress .circle.done {
background: #eee;
}
.progress .bar.active {
background: linear-gradient(to right, #EEE 40%, #FFF 60%);
}
.progress .circle.done .label {
color: #FFF;
background: #8bc435;
box-shadow: inset 0 0 2px rgba(0,0,0,.2);
}
.progress .circle.done .title {
color: #444;
}
.progress .circle.active .label {
color: #FFF;
background: #0c95be;
box-shadow: inset 0 0 2px rgba(0,0,0,.2);
}
.progress .circle.active .title {
color: #0c95be;
}
</style>
Here's my body elements with title
and circle
这是我带
title
和circle
身体元素
<div class="progress">
<div class="circle active">
<span class="label">1</span>
<span class="title">Ticket Requested</span>
</div>
<span class="bar"></span>
<div class="circle">
<span class="label">2</span>
<span class="title">Ticket Raised</span>
</div>
<span class="bar"></span>
<div class="circle">
<span class="label">3</span>
<span class="title">Completed</span>
</div>
</div>
And I'm doing this jQuery to alter the left
of my title
relative to circle
but it's not wotking. 我正在执行此jQuery,以将我的
title
的left
相对于circle
更改,但它不起作用。
$(document).ready(function(){
for (i=1;i<4;i++){
var pos = $('.progress .circle:nth-of-type(' + i + ')').position();
var widthLabel = $('.progress .circle:nth-of-type(' + i + ') .title').outerWidth();
$('.progress .circle:nth-of-type(' + i + ') .title').css({
position: "aboslute",
left: (pos.left - (widthLabel/2)) + "px"
});
}
});
The code u have given has the spelling mistake for position - absolute, Even if the spelling is corrected, it won't work as it needs to be relative to circle. 您提供的代码在位置上存在拼写错误-绝对错误,即使纠正了拼写,也无法正常工作,因为它需要相对于圆。
Try the following code 试试下面的代码
$(document).ready(function(){
for (i=1;i<4;i++){
var widthLabel = $('.progress .circle:nth-of-type(' + i + ') .title').outerWidth();
var widthCircle = $('.progress .circle:nth-of-type(' + i + ')').outerWidth();
$('.progress .circle:nth-of-type(' + i + ') .title').css({
position: "relative",
left: -((widthLabel/2) - (widthCircle/2)) + "px"
});
}
});
The label width is then subtracted with the circle width. 然后,将标签宽度减去圆宽度。 This will do it
这会做到的
Use this simple way 用这个简单的方法
$('.title').each(function(){ var width = $(this).width() / 2; $(this).css({marginLeft: -width}); });
*, *:after, *:before { margin: 0; padding: 0; box-sizing: border-box; font-family: "Open Sans"; } /* Form Progress */ .progress { /*width: 1500px;*/ width: 100%; /*demo use*/ margin: 20px auto; text-align: center; } .progress .circle, .progress .bar { display: inline-block; background: #fff; width: 40px; height: 40px; border-radius: 40px; border: 1px solid #d5d5da; } .progress .bar { position: relative; width: 100px; height: 6px; margin-left: -5px; margin-right: -5px; border-left: none; border-right: none; border-radius: 0; } .progress .circle{ position: relative; /* new changes*/ } .progress .circle .label { display: inline-block; width: 32px; height: 32px; line-height: 32px; border-radius: 32px; margin-top: 3px; color: #b5b5ba; font-size: 17px; } .progress .circle .title { color: #b5b5ba; font-size: 13px; line-height: 30px; margin-left: -5px; /* new changes*/ left: 50%; position: absolute; top: 33px; } /* Done / Active */ .progress .bar.done, .progress .circle.done { background: #eee; } .progress .bar.active { background: linear-gradient(to right, #EEE 40%, #FFF 60%); } .progress .circle.done .label { color: #FFF; background: #8bc435; box-shadow: inset 0 0 2px rgba(0,0,0,.2); } .progress .circle.done .title { color: #444; } .progress .circle.active .label { color: #FFF; background: #0c95be; box-shadow: inset 0 0 2px rgba(0,0,0,.2); } .progress .circle.active .title { color: #0c95be; }
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script> <div class="progress"> <div class="circle active"> <span class="label">1</span> <span class="title">Ticket Requested</span> </div> <span class="bar"></span> <div class="circle"> <span class="label">2</span> <span class="title">Ticket Raised</span> </div> <span class="bar"></span> <div class="circle"> <span class="label">3</span> <span class="title">Completed</span> </div> </div>
您已拼写位置:jQuery中的“绝对”错误。
I've moved your code to a fiddle but I failed to get it to work as you want it, instead I formated a slightly Thin approach without using javascript. 我已经将您的代码移到了一个小提琴,但未能按您的要求运行,而是我格式化了一个略显Thin的方法而未使用javascript。
https://fiddle.jshell.net/znrr38tv/ https://fiddle.jshell.net/znrr38tv/
Feel free to edit to your spects 随时编辑您的内容
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