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如何将多个查询的结果存储在不同的数组变量中

[英]How to store results of multiple queries in different array variables

I need to get data from 2 different queries. 我需要从2个不同的查询中获取数据。 I want to store them as 2 separate variables. 我想将它们存储为2个单独的变量。

First I tried this: 首先,我尝试了这个:

// 1. Create a database connection
$mysqli = new mysqli(DB_SERVER, DB_USER, DB_PASS, DB_NAME, DB_PORT);

if ($mysqli->connect_errno) {
    echo "No connection" ;
}
// 2. first query 
$query = "CALL sp1('2015-01-01', '2015-01-31');";
$result = $mysqli->query($query);

$var1 = array();
while($shop = $result->fetch_object()) {
    $var1[] = $shop;
}

echo '<pre>', print_r($var1), '</pre>';
$result->free();

// 3. second query 
$query = "CALL sp2('2015-01-01', '2015-01-31');";
$result = $mysqli->query($query);

$var2 = array();
while($shop = $result->fetch_object()) {
    $var2[] = $shop;
}

echo '<pre>', print_r($var2), '</pre>';

I get the data from 1st query however when php tries to fetch 2nd query I got this error: 我从第一个查询获取数据,但是当php尝试获取第二个查询时,出现此错误:

Fatal error: Call to a member function fetch_object() on boolean 致命错误:在布尔值上调用成员函数fetch_object()

I read about multi_query but couldn't find anything about saving output from queries as separate variables. 我读到有关multi_query的信息,但找不到有关将查询的输出另存为单独变量的任何信息。

Additional info: Even when I switch queries always the second one is not correct. 附加信息:即使我总是切换查询,第二个查询也不正确。 I don't know how to load second query and what is happening to the previous one (gets deleted when I write:result->free?) 我不知道如何加载第二个查询以及上一个查询发生了什么(我写:result-> free时被删除了)

The solution was this little line: 解决的方法是:

$results->free();
// solution
$mysqli->next_result();

It seems that mysqli needs information that one query is finished. 似乎mysqli需要一个查询已完成的信息。

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