Makefile中的嵌套命令替换

Question

I have a pretty basic makefile where I want to use the name of the current project / folder, but I keep having problems. I've tried:

example:
  docker build -t `basename `pwd`` .
  docker build -t `basename $(pwd)` # From what I know $() relates to a variable in makefiles.

Any ideas?

Answer 1

One approach:

docker build -t `basename $(PWD)`

This, like many environment variables, is all uppercase.

As was pointed out in the comments, this:

docker build -t $$(basename $$(pwd))

will also work. This is more akin to your first attempt, where the pwd command is used rather than the PWD environment variable.

And, this will also work:

docker build -t `basename \`pwd\``