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如何将元素放在Python队列的底部

[英]How to put elements on bottom of Python queue

I've a queue that is populated by different threads. 我有一个由不同线程填充的队列。 I've a thread where I get items from the queue and I send them to another destination. 我有一个线程,从队列中获取项目,然后将它们发送到另一个目的地。 When the last operation fails I want to put again the elements in the queue, but in the bottom of the queue because I want that the dequeuer Thread dequeue them as first priority. 当最后一个操作失败时,我想再次将元素放入队列中,但要放在队列的底部,因为我希望出队线程将它们作为第一优先级出队。 Is there a way to do that? 有没有办法做到这一点? Maybe using other class instead of Queue.queue? 也许使用其他类而不是Queue.queue?

How about a deque ? 双端队列怎么样?

Deques support thread-safe, memory efficient appends and pops from either side of the deque with approximately the same O(1) performance in either direction. 双端队列从双端队列的任一侧支持线程安全,内存高效的追加和弹出,并且在任一方向上的O(1)性能大致相同。

Here's an implementation -- it's basically Queue.put method with self._put(item) replaced by self.queue.appendleft(item) 这是一个实现-基本上是Queue.put方法,其中self._put(item)替换为self.queue.appendleft(item)

from Queue import Queue

class MyQueue(Queue):
    def putleft(self, item, block=True, timeout=None):
        self.not_full.acquire()
        try:
            if self.maxsize > 0:
                if not block:
                    if self._qsize() == self.maxsize:
                        raise Full
                elif timeout is None:
                    while self._qsize() == self.maxsize:
                        self.not_full.wait()
                elif timeout < 0:
                    raise ValueError("'timeout' must be a non-negative number")
                else:
                    endtime = _time() + timeout
                    while self._qsize() == self.maxsize:
                        remaining = endtime - _time()
                        if remaining <= 0.0:
                            raise Full
                        self.not_full.wait(remaining)
            self.queue.appendleft(item)
            self.unfinished_tasks += 1
            self.not_empty.notify()
        finally:
            self.not_full.release()

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