[英]Copiable mocks in Google Test Framework
Is it possible to make a mock class copiable in Google Test Framework ? 是否可以在Google Test Framework中复制模拟类? I've seen that the default copy constructor and copy assignment operator are deleted once that the MOCK_METHOD
macros are used. 我已经看到,一旦使用了MOCK_METHOD
宏, MOCK_METHOD
删除默认的复制构造函数和复制赋值运算符 。 Is there a way to workaround that? 有没有解决方法?
I cannot imagine any use case for copying mock objects. 我无法想象复制模拟对象的任何用例。 When you want to mimic real object with mock object - you shall have access to the very same object from code under test and from your test case code - so why copying needed? 当您想用模拟对象模拟真实对象时-您将可以从被测代码和测试用例代码访问同一对象-那么为什么需要复制?
Anyway - I see one method to make copying of mock object: You have to define wrapper on mock object - which shall be kept by std::shared_ptr
. 无论如何-我看到了一种复制模拟对象的方法:您必须在模拟对象上定义包装器-该包装器应由std::shared_ptr
保留。
An example: 一个例子:
class XxxMock : public XxxInterface
{
public:
MOCK_METHOD0(foo, void());
};
#include <memory>
class XxxSharedMock : public XxxInteface
{
public:
XxxSharedMock(std::shared_ptr<XxxMock> xxxMock = std::make_shared<XxxMock>())
: xxxMock(xxxMock)
{}
void foo() override
{
xxxMock->foo();
}
// having: XxxSharedMock xxxMock;
// do: EXPECT_CALL(xxxMock.mock(), foo());
XxxMock& mock() { return *xxxMock; }
XxxMock const& mock() const { return *xxxMock; }
privated:
std::shared_ptr<XxxMock> xxxMock;
};
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.